11 For about 10 years after the French Revolution, the French government attempted to base measures of time on multiples of ten: One week consisted of 10 days, one day consisted of 10 hours, one hour consisted of 100 minutes, and one minute consisted of 100 seconds. What are the ratios of (a) the French decimal week to the standard week and (b) the French decimal second to the standard second?

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Chapter1: Introduction And Vectors
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Problem 57P
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•11 For about 10 years after the French Revolution, the French
government attempted to base measures of time on multiples of
ten: One week consisted of 10 days, one day consisted of 10 hours,
one hour consisted of 100 minutes, and one minute consisted of 100
seconds. What are the ratios of (a) the French decimal week to the
standard week and (b) the French decimal second to the standard
second?
Transcribed Image Text:•11 For about 10 years after the French Revolution, the French government attempted to base measures of time on multiples of ten: One week consisted of 10 days, one day consisted of 10 hours, one hour consisted of 100 minutes, and one minute consisted of 100 seconds. What are the ratios of (a) the French decimal week to the standard week and (b) the French decimal second to the standard second?
The 2nd step to unit conversions is to re-write those equations so they are equal to 1. For exampleB
Iweek
=1
1mile
5280 ft
=1=
60 sec
or
1min
7days
or
5280 ft
=1 =
1 min
1mile
60 sec
lweek
7days
You may notice that since they are equal to 1, their reciprocal is also equal to 1. Whether we choose
the version on the left or its reciprocal (on the right) depends on what units we wish to cancel in the
term we eventually need to convert. The 4 relations you wrote above can also be written as "1", but
until we know what we're ultimately trying to convert we won't know whether to use the reciprocal
relation or not.
Now write down whether you see any way to relate the French system to our standard system; is
there some quantity which is the same between the two systems?
For part (a) in problem 11, is our day the same as the French day? Think about what actually
happens physically with the Earth during a standard day. Can our choice for a system of time
change the rotation of the Earth? Now you can write a 5th relation:
1 standard day =
French metric day (fill in the blank)
Another relation not asked for in the problem could also be determined. What is the relationship
between a standard year and a French metric year?
(more on back of page)
Hopefully you've got the 4 relations given in the problem and also realized that 1 standard day
equals 1 French metric day as the 5th relation.
To solve part (a), we need to relate 1 standard week to 1 metric week.
1 standard week = 7 standard days
1 metric week = 10 metric days
Part (a) doesn't require anything fancy, just find a way to relate the two systems. This is one way to
do it:
1standard week
=1 also
1metric week
=1
7standard days
10 metric days
Since both equations equal the same thing (1), they can be set equal to each other and you can re-
arrange to obtain an answer for part (a). Do this now:
For part (b) its vital to realize that you can multiply ANYTHING by 1 without changing its value!
This is how we can convert units for part (b) and in fact for any quantity in general. The four
relations you have written can be re-written as "1".
changing its value. Treat units as variables that can be cancelled if they appear in both the
denominator AND numerator. Here we will multiply one day by “l" three times!
You can multiply any quantity by 1 without
As a start:
1 day
is the same as: (1 day) 24 standard hours | 60 standard minutes 60 standard seconds
1 standard mintte-,
Fstandard day
1standard-hour
is the same as: 86,400 standard seconds. Note how the units cancelled, leaving just seconds.
From this point, you should have a good basis to figure out part (b), which asks you to relate the
length of a standard second to the length of a metric second. Work part (b) in the space below.
Transcribed Image Text:The 2nd step to unit conversions is to re-write those equations so they are equal to 1. For exampleB Iweek =1 1mile 5280 ft =1= 60 sec or 1min 7days or 5280 ft =1 = 1 min 1mile 60 sec lweek 7days You may notice that since they are equal to 1, their reciprocal is also equal to 1. Whether we choose the version on the left or its reciprocal (on the right) depends on what units we wish to cancel in the term we eventually need to convert. The 4 relations you wrote above can also be written as "1", but until we know what we're ultimately trying to convert we won't know whether to use the reciprocal relation or not. Now write down whether you see any way to relate the French system to our standard system; is there some quantity which is the same between the two systems? For part (a) in problem 11, is our day the same as the French day? Think about what actually happens physically with the Earth during a standard day. Can our choice for a system of time change the rotation of the Earth? Now you can write a 5th relation: 1 standard day = French metric day (fill in the blank) Another relation not asked for in the problem could also be determined. What is the relationship between a standard year and a French metric year? (more on back of page) Hopefully you've got the 4 relations given in the problem and also realized that 1 standard day equals 1 French metric day as the 5th relation. To solve part (a), we need to relate 1 standard week to 1 metric week. 1 standard week = 7 standard days 1 metric week = 10 metric days Part (a) doesn't require anything fancy, just find a way to relate the two systems. This is one way to do it: 1standard week =1 also 1metric week =1 7standard days 10 metric days Since both equations equal the same thing (1), they can be set equal to each other and you can re- arrange to obtain an answer for part (a). Do this now: For part (b) its vital to realize that you can multiply ANYTHING by 1 without changing its value! This is how we can convert units for part (b) and in fact for any quantity in general. The four relations you have written can be re-written as "1". changing its value. Treat units as variables that can be cancelled if they appear in both the denominator AND numerator. Here we will multiply one day by “l" three times! You can multiply any quantity by 1 without As a start: 1 day is the same as: (1 day) 24 standard hours | 60 standard minutes 60 standard seconds 1 standard mintte-, Fstandard day 1standard-hour is the same as: 86,400 standard seconds. Note how the units cancelled, leaving just seconds. From this point, you should have a good basis to figure out part (b), which asks you to relate the length of a standard second to the length of a metric second. Work part (b) in the space below.
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