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Social Science#11. (10 points) A 150 [g] particle at x 0 is moving at 2.00 [m/s] in the +x-directionAs it moves, it experiences a force given by F (0.250) sin ( What is the2.00particle's speed when it reaches r= 3.14 [m]?
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![#11. (10 points) A 150 [g] particle at x 0 is moving at 2.00 [m/s] in the +x-direction
As it moves, it experiences a force given by F (0.250) sin ( What is the
2.00
particle's speed when it reaches r= 3.14 [m]?](https://prod-qna-question-images.s3.amazonaws.com/qna-images/question/513884ca-388b-4bcf-9ead-90744125fdd1/bc660646-0c44-4a43-9443-192faa58b867/oeexy78.jpeg)
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#11. (10 points) A 150 [g] particle at x 0 is moving at 2.00 [m/s] in the +x-direction As it moves, it experiences a force given by F (0.250) sin ( What is the 2.00 particle's speed when it reaches r= 3.14 [m]?
Expert Answer
the work done is equal to the change in kinetic energy,
the work done is,
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Fdx
integrate the above equation by substituting the given values,
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T- 3.14 X W 0.250sin dx 2.00 3.14m (0.250) -cos 2.00 3.14m 0.500 1-cos 2.00 =0.4996J
the change in kinetic ...
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AK = m(v-u2)
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