[² 11. [(2 sinx+cos.x) dx 9. 13. 15. x¹/3 19. 21. 3 x2/3 - dx 17. [(3 cos x - 2) dx [(5x- 2²/1) dx √x²+4 [2 sec. 2 sec x tan x dx [ 5 sec² x dx 10. [³ 12. [(3 cos 14. 16. √(1-x)² 4 COS X sin x [ (4x - 2 sin.x) dx 18. x+2x³/4 x5/4 20. 3 cos x - sinx) dx dx 4. dx dx [(2 cos x - √x³) dx 22₁ [1-cos² x dx

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
10:01
9.
11.
13.
15.
17.
19.
21.
23.
S
[(2)
x¹/3 3
x2/3
S
(2 sin x + cos x) dx
+252 63 4828884
27 June, 14:06
2 sec x tan x dx
[5 5 sec² x dx
[(3
(3 cosx-2) dx
[(5x - 12/17) dx
25. (a)
+4
fx² + 4 dx
[x¹/4 (x³/4 - 4) dx
26. (a)
27. (a)
dx
28. (a)
[√x³
/x³ +4 dx
3x² 4
|||
dx
2 secx dx
f2
ƒ ( 12/27 - 1) dx
10.
12.
14.
16.
(3 co
(3 cos x
・fa=x²₁
18.
20.
22.
24.
√x+
In exercises 25-28, one of the two antiderivatives can be deter-
mined using basic algebra and the derivative formulas we have
presented. Find the antiderivative of this one and label the other
"N/A."
{ | | 95%-
x + 2x³/4
x5/4
4
COS X
I
dx
sin x
[ (4x
(4x - 2 sin x) dx
[(2 co
(2 cos x --
1
1 - cos²x
cos²x
dx
[x²/3 (x−4/3 — 3) dx
(b)
(b) f
dx
sin x) dx
dx
3x²
(b) / (√x³ + 4) dx
x²
4
√x³) dx
dx
[s
[ see² x dx
(b) 1₁²²= 7 dx
Transcribed Image Text:10:01 9. 11. 13. 15. 17. 19. 21. 23. S [(2) x¹/3 3 x2/3 S (2 sin x + cos x) dx +252 63 4828884 27 June, 14:06 2 sec x tan x dx [5 5 sec² x dx [(3 (3 cosx-2) dx [(5x - 12/17) dx 25. (a) +4 fx² + 4 dx [x¹/4 (x³/4 - 4) dx 26. (a) 27. (a) dx 28. (a) [√x³ /x³ +4 dx 3x² 4 ||| dx 2 secx dx f2 ƒ ( 12/27 - 1) dx 10. 12. 14. 16. (3 co (3 cos x ・fa=x²₁ 18. 20. 22. 24. √x+ In exercises 25-28, one of the two antiderivatives can be deter- mined using basic algebra and the derivative formulas we have presented. Find the antiderivative of this one and label the other "N/A." { | | 95%- x + 2x³/4 x5/4 4 COS X I dx sin x [ (4x (4x - 2 sin x) dx [(2 co (2 cos x -- 1 1 - cos²x cos²x dx [x²/3 (x−4/3 — 3) dx (b) (b) f dx sin x) dx dx 3x² (b) / (√x³ + 4) dx x² 4 √x³) dx dx [s [ see² x dx (b) 1₁²²= 7 dx
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