11. Consider two thin lenses (one converging and one diverging) aligned on a common axis, running left to right, the converging lens being on the left and the diverging being on the right, as shown on the figure. The converging lens has a focal length of +6.00 cm and the diverging lens has a focal length of –8.00 cm. A distance of 18.0 cm separates the lenses. An object is located at a distance of 12.0 cm to the left of the converging lens. What type of final image will you get (i.e. real vs. virtual, orientation and magnification compared to the original object)? Lens 1 Lens 2 |object near f, far f, near f, far f2 a. The final image will be real, inverted and magnified compared to the original object. b. The final image will be virtual, inverted and magnified compared to the original object. c. The final image will be virtual, upright and magnified compared to the original object. d. The final image will be real, upright and diminished compared to the original object. e. The final image will be virtual, inverted and diminished compared to the original object.

11. Consider two thin lenses (one converging and one diverging) aligned on a common axis, running left to right, the converging lens being on the left and the diverging being on the right, as shown on the figure. The converging lens has a focal length of +6.00 cm and the diverging lens has a focal length of –8.00 cm. A distance of 18.0 cm separates the lenses. An object is located at a distance of 12.0 cm to the left of the converging lens. What type of final image will you get (i.e. real vs. virtual, orientation and magnification compared to the original object)? Lens 1 Lens 2 |object near f, far f, near f, far f2 a. The final image will be real, inverted and magnified compared to the original object. b. The final image will be virtual, inverted and magnified compared to the original object. c. The final image will be virtual, upright and magnified compared to the original object. d. The final image will be real, upright and diminished compared to the original object. e. The final image will be virtual, inverted and diminished compared to the original object.

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter26: Image Formation By Mirrors And Lenses

Section: Chapter Questions

Problem 3OQ

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Similar questions

The near point of an eye is 75.0 cm. (a) What should be the power of a corrective lens prescribed to enable the eye to see an object clearly at 25.0 cm? (b) If, using the corrective lens, the person can see an object clearly at 26 0 cm but not at 25.0 cm, by how many diopters did the lens grinder miss the prescription?
A diverging lens has a focal length of magnitude 20.0 cm. (a) Locate the image for object distances of (i) 40.0 cm, (ii) 20.0 cm, and (iii) 10.0 cm. For each case, state whether the image is (b) real or virtual and (c) upright or inverted.(d) For each case, find the magnification.
A diverging lens has a focal length of magnitude 20.0 cm (a) Locate the images for object distances of (i) 40.0 cm. (ii) 20.0 cm, and (iii) 10.0 cm. For each case, state whether the image is (b) real or virtual and (c) upright or inverted. (d) For each case, Find the magnification.
A converging lens has a focal length of 10.0 cm. Locate the object if a real image is located at a distance from the lens of (a) 20.0 cm and (b) 50.0 cm. What If? Redo the calculations if the images are virtual and located at a distance from the lens of (c) 20.0 cm and (d) 50.0 cm.
A particular nearsighted patient cant see objects clearly beyond 15.0 cm from their eye. Determine (a) the lens power required to correct the patients vision and (b) the type of lens required (converging or diverging). Neglect the distance between the eye and the corrective lens.