11. In Fig. 1, the resistances are R110.0 V and ɛ2 = 20.0 V, ɛ3 =by step solution)20.0 2 and R2 = 30.0 2, and the ideal batteries have emfs15.0 V. What is the voltage across R2? (Fig.1) (Show step%3DEj =RRFig.1R2RR3.English (United States)K Accessibility: Unavailable一你要搜索的内容

We have a circuit with 3 batteries of EMF E1=10 V, E2=15 V and E3= 30 V and with resistances R1=20…

11. In Fig. 1, the resistances are R1 = 20.0 2 and R2 30.0 2, and the ideal batteries have emfs ɛ1 = 10.0 V and ɛ2 %3D 20.0 V, E3 = 15.0 V. What is the voltage across R22 (Fig.1) (Show step by step solution) R R Fig.1 R2 R R b. 3.

11. In Fig. 1, the resistances are R1 = 20.0 2 and R2 30.0 2, and the ideal batteries have emfs ɛ1 = 10.0 V and ɛ2 %3D 20.0 V, E3 = 15.0 V. What is the voltage across R22 (Fig.1) (Show step by step solution) R R Fig.1 R2 R R b. 3.

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter28: Direct-current Circuits

Section: Chapter Questions

Problem 28.21P: Consider the circuit shown in Figure P28.21 on page 860. (a) Find the voltage across the 3.00-0...

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A child’s electronic toy is supplied by three 1.58-V alkaline cells having internal resistances of 0.0200 in series with a 1.53-V carbon-zinc dry cell having a 0.100- internal resistance. The load resistance is 10.0 . (a) Draw a circuit diagram of the toy and its batteries, (b) What current flows? (c) How much power is supplied to the load? (d) What is the internal resistance of the dry cell if it goes bad, resulting in only 0.500 W being supplied to the load?
Integrated Concepts A 12.0-V emf automobile battery has a terminal voltage of 16.0 V when being charged by a current of 10.0 A. (a) What is the battery’s internal resistance? (b) What power is dissipated inside the battery? (c) At what rate (in °C/min ) will its temperature increase if its mass is 20.0 kg and it has a specific heat of 0.300 kcal/kg. °C, assuming no heat escapes?
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When a straight wire is heated, its resistance changes according to the equation R = R0 [1 + (T T0)] (Eq. 17.7), where is the temperature coefficient of resistivity. (a) Show that a more precise result, which includes the length and area of a wire change when it is heated, is R=R0[1+(TT0)][1+(TT0)][1+2(TT0)] where is the coefficient of linear expansion. (See Topic 10.) (b) Compare the two results for a 2.00-m-long copper wire of radius 0.100 mm, starting at 20.0C and heated to 100.0C.
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