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- 1.Given a positive integer, N, the ’3N+1’ sequence starting from N is defined as follows:If N is an even number, then divide N by two to get a new value for NIf N is an odd number, then multiply N by 3 and add 1 to get a new value for N.Continue to generate numbers in this way until N becomes equal to 1For example, starting from N = 3 the complete ’3N+1’ sequence would be:3, 10, 5, 16, 8, 4, 2, 1Write c++ code to ask the user to enter a positive integer (N) in the main() function. Write a function sequence()that receives the integer value N and display the ‘3N+1’ sequence starting from the integer value that wasreceived (entered by the user). The function must also count and return the numbers that the sequenceconsists of. The returned value must be displayed from the main() function.21 السؤال Consider f(n)= 7 log (7) , g(n)= 9 log (9) which of the following is true? Theta = θ Omega = Ω الاجابات f(n)=O(G(n)) f(n)=Theta (g(n)) f(n)=Omega(g(n)) g(n)= O(f(n))Given a positive integer, N, the ’3N+1’ sequence starting from N is defined as follows: If N is an even number, then divide N by two to get a new value for N. If N is an odd number, then multiply N by 3 and add 1 to get a new value for N. Continue to generate numbers in this way until N becomes equal to 1. For example, starting from N = 3 the complete ’3N+1’ sequence would be:3, 10, 5, 16, 8, 4, 2, 1 Do the following: Write a code in C++ to ask the user to enter a positive integer (N) in the main() function. Write a function sequence() that receives the integer value N and display the ‘3N+1’ sequence starting from the integer value that wasreceived (entered by the user). The function must also count and return the numbers that the sequence consists of. The returned value must be displayed from the main() function. Example input and output is given in the following image.
- Explain....... 1.Given f(n)=3nlgn+2. State if the following are true (T) or false (F): i) f(n) =O(n), ii) f(n)=Ω(n2) a. i: F, ii: F b. i: F, ii: T c. i: T, ii: T d. i: T, ii: F 2. Given f(n)=3n+2. State if the following are true (T) or false (F): i) f(n) =Θ(n), ii) f(n)=O(lgn) a. i: F, ii: F b. i: F, ii: T c. i: T, ii: T d. i: T, ii: F23 Consider f(n) = 5 n log n , and g(n)= (n+5) which of the following is true الاجابات f(n)= O(g(n)) f(n)= omega (g(n)) f(n)= theta (g(n) g(n) = O(f(n))Given a positive integer, N, the ’3N+1’ sequence starting from N is defined as follows:If N is an even number, then divide N by two to get a new value for NIf N is an odd number, then multiply N by 3 and add 1 to get a new value for N.Continue to generate numbers in this way until N becomes equal to 1For example, starting from N = 3 the complete ’3N+1’ sequence would be:3, 10, 5, 16, 8, 4, 2, 1Write code to ask the user to enter a positive integer (N) in the main() function. Write a function sequence()that receives the integer value N and display the ‘3N+1’ sequence starting from the integer value that wasreceived (entered by the user). The function must also count and return the numbers that the sequenceconsists of. The returned value must be displayed from the main() function.
- Can someone help me to answer this activity? Factorial of a number is defined as: n! = n(n-1)(n-2)(n-3)...(2)(1) For example, 4! = 4*3*2*1 The n! can be written in terms of (n-1)! as: n! = n* (n-1)! (n-1)! = (n-1)*(n-2)! and so forth. Thus, in order to compute n!, we need (n-1)!, to have (n-1)!, we need (n-2)! and so forth. As you may immediately notice, the base case for factorial is 1 because 1! = 1. Write a program that uses a recursive function called factorial that takes an integer n as its argument and returns n! to the main.13( Calculate the time complexity of the following code and represent it in Big-oh(o) Notation. int a=2, b=3, c; c= a + b; cout << c; a. O(log n) b. O(nlog n) c. O(1) d. O( n )Computer Science Provide a recursive definition for the following set S. ?={2k3m5n ∈ ? | ?, ?, ? ∈ ?+} Z+ is the set of all positive integers (1, 2, 3, ...) N is a set of numbers so 2^1 * 3^1 * 5^1 = 35
- What is the big-O behavior of the following code segment? Explain. i = n; while ( i > 0 ) { for (j=1; j<n; ++j ) { . . . } i = i / 2; }Show that the following statements are equivalent, where n is an integergreater than or equal to 2. “n is even” and “n – 1 is odd”2. “n is even” and “n2 is even”3. “n – 1 is odd” and “n2 is even”4.2) (L4) Give truth values for the propositional variables that cause the two expressions to have different truth values. For example, given p ∨ q and p ⊕ q, the correct answer would be p = q = T, because when p and q are both true, p ∨ q is true but p ⊕ q is false. Note that there may be more than one correct answer. r ∧ (p ∨ q) (r ∧ p) ∨ q