11.92. Prove: (a) If am + bn = 1, then gcd(a, b) = 1; (b) If a = bq +r, then gcd(a, b) = gcd(b, r).

College Algebra
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ISBN:9781938168383
Author:Jay Abramson
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Chapter9: Sequences, Probability And Counting Theory
Section9.1: Sequences And Their Notations
Problem 71SE: Prove the conjecture made in the preceding exercise.
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11.92. Prove: (a) If am + bn = 1, then gcd(a, b) = 1; (b) If a = bq +r, then gcd(a, b) = gcd(b, r).
Transcribed Image Text:11.92. Prove: (a) If am + bn = 1, then gcd(a, b) = 1; (b) If a = bq +r, then gcd(a, b) = gcd(b, r).
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