12. A solid sphere of radius 40.0 cm has a total positive charge of 38.4 μC uniformly distributed throughout its volume. Calculate the magnitude of the electric field at the following distances. (a) 0 cm from the center of the sphere E = ke Qr no keQr 3 10 0.100m (b) 10.0 cm from the center of the sphere E = Ke Qr = (8.99 X 10' N. 14² (c) (38.4×106) (0.10cm) 4> 10.4004) = 579.4 KW/C =0.400m (c) 40.0 cm from the center of the sphere 3 E= Ke Q = (894 × 109 N.m/c) (38.4 x 10" c) x (0.400m 12 =2/57.6 KN/C 0.635 (d) 63.5 cm from the center of the sphere I- Ke Q (8.99 x 10' W.²/c) (8.4×10°C) (0.675)2 = 356 KN/0 The direction for each electrificht is rudiully outward
12. A solid sphere of radius 40.0 cm has a total positive charge of 38.4 μC uniformly distributed throughout its volume. Calculate the magnitude of the electric field at the following distances. (a) 0 cm from the center of the sphere E = ke Qr no keQr 3 10 0.100m (b) 10.0 cm from the center of the sphere E = Ke Qr = (8.99 X 10' N. 14² (c) (38.4×106) (0.10cm) 4> 10.4004) = 579.4 KW/C =0.400m (c) 40.0 cm from the center of the sphere 3 E= Ke Q = (894 × 109 N.m/c) (38.4 x 10" c) x (0.400m 12 =2/57.6 KN/C 0.635 (d) 63.5 cm from the center of the sphere I- Ke Q (8.99 x 10' W.²/c) (8.4×10°C) (0.675)2 = 356 KN/0 The direction for each electrificht is rudiully outward
Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter25: Gauss’s Law
Section: Chapter Questions
Problem 63PQ
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![12. A solid sphere of radius 40.0 cm has a total positive charge of 38.4 μC uniformly
distributed throughout its volume. Calculate the magnitude of the electric field at the
following distances.
(a) 0 cm from the center of the sphere
E = ke Qr no
keQr
3
10
0.100m
(b) 10.0 cm from the center of the sphere
E = Ke Qr = (8.99 X 10' N. 14² (c) (38.4×106) (0.10cm)
4>
10.4004)
= 579.4 KW/C
=0.400m
(c) 40.0 cm from the center of the sphere
3
E= Ke Q = (894 × 109 N.m/c) (38.4 x 10" c)
x
(0.400m 12
=2/57.6 KN/C
0.635
(d) 63.5 cm from the center of the sphere
I- Ke Q
(8.99 x 10' W.²/c) (8.4×10°C)
(0.675)2
= 356 KN/0
The direction for each electrificht is rudiully outward](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F67e09a10-39fc-48c9-94ba-1077403f7747%2F259ea6eb-772b-4997-b60b-41130f396153%2F9wedyi_processed.jpeg&w=3840&q=75)
Transcribed Image Text:12. A solid sphere of radius 40.0 cm has a total positive charge of 38.4 μC uniformly
distributed throughout its volume. Calculate the magnitude of the electric field at the
following distances.
(a) 0 cm from the center of the sphere
E = ke Qr no
keQr
3
10
0.100m
(b) 10.0 cm from the center of the sphere
E = Ke Qr = (8.99 X 10' N. 14² (c) (38.4×106) (0.10cm)
4>
10.4004)
= 579.4 KW/C
=0.400m
(c) 40.0 cm from the center of the sphere
3
E= Ke Q = (894 × 109 N.m/c) (38.4 x 10" c)
x
(0.400m 12
=2/57.6 KN/C
0.635
(d) 63.5 cm from the center of the sphere
I- Ke Q
(8.99 x 10' W.²/c) (8.4×10°C)
(0.675)2
= 356 KN/0
The direction for each electrificht is rudiully outward
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