12. Start with Equation IVb.2.8 and obtain Equation IVb.2.9. For this purpose, first ignore the non-linear term compared with the two dominant terms. Then sub- stitute for the velocity and temperature profiles. To develop the integral, consider a case where the hydrodynamic boundary layer is thicker than the thermal bound- ary layer (thus the integral is zero for y > 8'). Arrange the result in terms of = 8'18 and ignore *.

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Chapter6: Forced Convection Over Exterior Surfaces
Section: Chapter Questions
Problem 6.21P
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12. Start with Equation IVb.2.8 and obtain Equation IVb.2.9. For this purpose,
first ignore the non-linear term compared with the two dominant terms. Then sub-
stitute for the velocity and temperature profiles. To develop the integral, consider
a case where the hydrodynamic boundary layer is thicker than the thermal bound-
ary layer (thus the integral is zero for y > 8'). Arrange the result in terms of =
8'/8 and ignore *.
Transcribed Image Text:12. Start with Equation IVb.2.8 and obtain Equation IVb.2.9. For this purpose, first ignore the non-linear term compared with the two dominant terms. Then sub- stitute for the velocity and temperature profiles. To develop the integral, consider a case where the hydrodynamic boundary layer is thicker than the thermal bound- ary layer (thus the integral is zero for y > 8'). Arrange the result in terms of = 8'/8 and ignore *.
*AP.
dy
dy
ƏT
IVb.2.8
dx
pCp
dồ
= 10a
Sp
dx
where = 8'/8. Introducing Equation IVb.2.7 and rearranging, we find the follow-
ing differential equation:
4 dž
+5
3" dx
13 a
-x-
14 v
where = . The boundary conditions for this differential equation is = 0 (since
8 = 0) at x = x,o. Thus
1
3/4 71/3
r-1/3
5= 1.026
IVb.2.9
8'
If the plate is heated at the leading edge then = 88 = ( Pr/1.026).
Transcribed Image Text:*AP. dy dy ƏT IVb.2.8 dx pCp dồ = 10a Sp dx where = 8'/8. Introducing Equation IVb.2.7 and rearranging, we find the follow- ing differential equation: 4 dž +5 3" dx 13 a -x- 14 v where = . The boundary conditions for this differential equation is = 0 (since 8 = 0) at x = x,o. Thus 1 3/4 71/3 r-1/3 5= 1.026 IVb.2.9 8' If the plate is heated at the leading edge then = 88 = ( Pr/1.026).
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