12. Write the equation of circle R., given R(3, −2) and Q(-7, 13) are points on the circle. O (x+7)² + (y- 13)² = 325 (x − 3)² + (y + 2)² = √√325 - O (x − 3)² + (y + 2)² = 325 O (x+3)² + (y - 2)² = 325
12. Write the equation of circle R., given R(3, −2) and Q(-7, 13) are points on the circle. O (x+7)² + (y- 13)² = 325 (x − 3)² + (y + 2)² = √√325 - O (x − 3)² + (y + 2)² = 325 O (x+3)² + (y - 2)² = 325
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter11: Topics From Analytic Geometry
Section11.3: Hyperbolas
Problem 38E
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Please help me solve this practice question I found online
![12. Write the equation of circle R., given R(3, -2) and
Q(-7, 13) are points on the circle.
O (x+7)² + (y - 3)² = 325
O (x − 3)² + (y + 2)² = √325
O (x − 3)² + (y + 2)² = 325
O (x+3)² + (y — 2)² = 325](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9dd90036-49a7-463c-a41d-3cee85eff577%2F8c015d31-a044-4eec-ad38-fa03a5eed875%2Fnx9z0a_processed.png&w=3840&q=75)
Transcribed Image Text:12. Write the equation of circle R., given R(3, -2) and
Q(-7, 13) are points on the circle.
O (x+7)² + (y - 3)² = 325
O (x − 3)² + (y + 2)² = √325
O (x − 3)² + (y + 2)² = 325
O (x+3)² + (y — 2)² = 325
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