please explain why child D is 18% I don't understand the given explanation. explain thoroughly and in simple terms 12.37. The pedigrees indicated here were obtained with three unrelated familieswhose members express the same completely penetrant disease caused by adominant mutation that is linked at a distance of 10 cM from an SSR markerlocus with three alleles numbered 1, 2, and 3. The SSR alleles present withineach live genotype are indicated below the pedigree symbol. The phenotypes ofthe newly born labeled individuals-A, B, C, and D-are unknown.a. What is the probability of disease expression in each of these newbornbabies?b. Why would a human geneticist be unlikely to use this SSR marker fordiagnosis of the genetic disease?13221322123212 321232123212321232AD In the pedigree at the right, the phase of the alleles in the male parent is not known.However, we can use the information that the sibling of Child D is affected to12-24ight © 2021 McGraw-Hill Education. All rights reserved. No reproduction or distribution without the priorwritten consent of McGraw-Hill Education.chapter 12determine the likelihood of one phase or the other. The brother of Child D inheritedDml from his father. This means that the chance is 90% that the genotype of the fatheris D ml / d m2, and the chance is 10% that his genotype is d m1 / D m2. Child Dinherited m2 from his father. The probability that Child D inherited m2 D from hisfather is the weighted sum of the chances of inheriting this chromosome given each ofthe father's possible genotypes above. If the father's genotype is D m1/ d m2, thenusing the same logic as we did above for Children A-C, there are 9 d m2 gametesproduced forthe father's genotype is d m1/D m2, the relative chance of D m2 is 90%. Therefore,the chance that Child D has the disease (inherited D m2) is: (0.9)(0.1) + (0.1)(0.9)= 0.09 + 0.09 = 0.18, or 18%.every1 D m2 gamete made, and so the relative chance of D m2 is 10%. If%3D

A pedigree chart is a diagram that shows the occurrence and appearance of phenotypes of a particular…

12.37. The pedigrees indicated here were obtained with three unrelated families whose members express the same completely penetrant disease caused by a dominant mutation that is linked at a distance of 10 cM from an SSR marker locus with three alleles numbered 1, 2, and 3. The SSR alleles present within each live genotype are indicated below the pedigree symbol. The phenotypes of the newly born labeled individuals-A, B, C, and D-are unknown. a. What is the probability of disease expression in each of these newborn babies? b. Why would a human geneticist be unlikely to use this SSR marker for diagnosis of the genetic disease? 13 22 13 22 12 32 12 32 12 32 12 32 12 32 12 32

12.37. The pedigrees indicated here were obtained with three unrelated families whose members express the same completely penetrant disease caused by a dominant mutation that is linked at a distance of 10 cM from an SSR marker locus with three alleles numbered 1, 2, and 3. The SSR alleles present within each live genotype are indicated below the pedigree symbol. The phenotypes of the newly born labeled individuals-A, B, C, and D-are unknown. a. What is the probability of disease expression in each of these newborn babies? b. Why would a human geneticist be unlikely to use this SSR marker for diagnosis of the genetic disease? 13 22 13 22 12 32 12 32 12 32 12 32 12 32 12 32

Biology 2e

2nd Edition

ISBN:9781947172517

Author:Matthew Douglas, Jung Choi, Mary Ann Clark

Publisher:Matthew Douglas, Jung Choi, Mary Ann Clark

Chapter12: Mendel's Experiments And Heredity

Section: Chapter Questions

Problem 29CTQ: Why is it more efficient to perform a test cross with a homozygous recessive donor than a homozygous...

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