125 mg of solid drug is placed in solution. Over time the drug dissolves. The amount of undissolved drug in mg was monitored as a function of time in minutes. The data was graphed with the following results: Amount of drug remaining vs. time: best fit is y = -11.4x + 125 R2 = 0.990 ln(Amount of drug remaining) vs. time: best fit is y = -0.114x + 4.84 R2 = 0.976 How much drug (in mg) remains after 5 minutes?
125 mg of solid drug is placed in solution. Over time the drug dissolves. The amount of undissolved drug in mg was monitored as a function of time in minutes. The data was graphed with the following results: Amount of drug remaining vs. time: best fit is y = -11.4x + 125 R2 = 0.990 ln(Amount of drug remaining) vs. time: best fit is y = -0.114x + 4.84 R2 = 0.976 How much drug (in mg) remains after 5 minutes?
Medical Terminology for Health Professions, Spiral bound Version (MindTap Course List)
8th Edition
ISBN:9781305634350
Author:Ann Ehrlich, Carol L. Schroeder, Laura Ehrlich, Katrina A. Schroeder
Publisher:Ann Ehrlich, Carol L. Schroeder, Laura Ehrlich, Katrina A. Schroeder
ChapterCom: Comprehensive Medical Terminology Review
Section: Chapter Questions
Problem 14SFT
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125 mg of solid drug is placed in solution. Over time the drug dissolves. The amount of undissolved drug in mg was monitored as a function of time in minutes. The data was graphed with the following results:
Amount of drug remaining vs. time: best fit is y = -11.4x + 125 R2 = 0.990 ln(Amount of drug remaining) vs. time: best fit is y = -0.114x + 4.84 R2 = 0.976
How much drug (in mg) remains after 5 minutes?
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