Answer 3-5. Need only letters. Grade level and Section:I. Match Column A in its correct equation in Column B. Write the correct letter bDate:number.Column AColumn B1. 15°A. sin(45°- 30°) = sin 45° cos 30° + cos 45° sin 30°B. cos(45°-30°) = cos 45° cos 30° + sin 45° sin 30°2. 75°A. sin(45° + 30°) = sin 45° cos 30° + cos 45° sin 30°B. cos(45° + 30°)E cos 45° cos 30° + sin 45° sin 30°133.36A. sin (+5 = sin cosB. sin (- = sin cos- cos sin+ cos Sin6.sinCOS5元4.36A. cos(- = cos cos+ sin sinB. cos-) = sin sin+ cos-cosCOS6.5. 105°A. tan(60° + 45°) =tan 60°-tan 45°1+tan 60°tan45°B. tan(60° +45°) =tan 60°+tan 45°1-tan 60°tan45°II. Use the sum and difference identities to write expressions as a single trigonorfunction angle.

Name: Answer 3-5. Need only letters. Grade level and Section:I. Match Column
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Description: Answer 3-5. Need only letters. Grade level and Section:I. Match Column A in its correct equation in Column B. Write the correct letter bDate:number.Column AColumn B1. 15°A. sin(45°- 30°) = sin 45° cos 30° + cos 45° sin 30°B. cos(45°-30°) = cos 45° co

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Math

Trigonometry

13 7 3. 36 A. sin (+5 = sin cos+ cos sin %3D B. sin (" – ) = sin cos- cos-sin sin 9. 4. 36 A. cos- = cos cos+ sin sin B. cas( -) = sin" sin+ cos cos COS %3D tan 60°-tan 45° 5. 105° A. tan(60° + 45°) 1+tan 60°tan45° tan 60°+tan 45° B. tan(60° + 45°) = 1-tan 60°tan45°

13 7 3. 36 A. sin (+5 = sin cos+ cos sin %3D B. sin (" – ) = sin cos- cos-sin sin 9. 4. 36 A. cos- = cos cos+ sin sin B. cas( -) = sin" sin+ cos cos COS %3D tan 60°-tan 45° 5. 105° A. tan(60° + 45°) 1+tan 60°tan45° tan 60°+tan 45° B. tan(60° + 45°) = 1-tan 60°tan45°

Mathematics For Machine Technology

8th Edition

ISBN:9781337798310

Author:Peterson, John.

Publisher:Peterson, John.

Chapter67: Analysis Of Trigonometric Functions

Section: Chapter Questions

Problem 13A: Refer to the following figure in answering Exercises 7 through 13. It may be helpful to sketch...

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