The answer is E.) 5.79 x 10^22.I don't know if my lack of rounding appropriate numbers is giving me incorrect answers but I'm sure I've done everything correctly. 13) How many oxygen atoms are contained in 2.74 g of aluminum sulfate?A) 12B) 6.02 x 1023C) 8.01 x 10-3D) 7.22 x 1024E) 5.79 x 102213) look @ 23Unit 3 Hin (cont.) (Do I need to round?and?)-213.) how many 0 atoms are contained in 2.74g of aluminum sulfate. A1² 504 ²A1: 26.9813386 (2) 53.963877222E.) s.79x10²5:32.06510:13.9994wwwwwwwww12.74g. 1 mol: Al. 504(1) = 32.655 g/mal(4) =63.9776gland)* PROBLEMY (It's not 4.63 it's 4-15.49)15.999463-99269_11688227-463%g derve15.0.8256772g/molMAHARVARAPAREMATANDSVIN(Okay hold on... AGAIN I don't understand.)WIVAAAAMwww.whmmC1002.745 15³1 A1₂ 504=convert to male, convert to mole, convert to mole convert to mole7.16882246274mand4 moli1 mol: A1² 504150.0256772queto get close to the answer I can subtract 6.022 butil must be setting it up wining.43810158.8256772.glimal 1 mal Al 5044 mol: 0do you... 2.74-1.168822746? I don't think 3042.65776445%.why? I am0-29220568715.999491m610n6.2922 856872.74↓11.7998832% 050...so lost.175.353424158.8256772=(180)1.1168822746

Answered: Image /qna-images/answer/790cda52-6980-4083-8c99-8301ac20fcb2.jpg

Answered: 13) How many oxygen atoms are contained…

Science

Chemistry

13) How many oxygen atoms are contained in 2.74 g of aluminum sulfate? A) 12 B) 60 x 1023 13)

Introductory Chemistry For Today

8th Edition

ISBN:9781285644561

Author:Seager

Publisher:Seager

Chapter2: Atoms And Molecules

Section: Chapter Questions

Problem 2.84E

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Concept explainers

Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "element" whereas “metron” means "measure".

Question

100%

The answer is E.) 5.79 x 10^22.
I don't know if my lack of rounding appropriate numbers is giving me incorrect answers but I'm sure I've done everything correctly.

13) How many oxygen atoms are contained in 2.74 g of aluminum sulfate?
A) 12
B) 6.02 x 1023
C) 8.01 x 10-3
D) 7.22 x 1024
E) 5.79 x 1022
13)

look @ 23
Unit 3 Hin (cont.) (Do I need to round?
and?)
-2
13.) how many 0 atoms are contained in 2.74g of aluminum sulfate. A1² 504 ²
A1: 26.9813386 (2) 53.9638772
22
E.) s.79x10²
5:32.065
10:13.9994
wwwwwwwww
12.74g. 1 mol: Al. 504
(1) = 32.655 g/mal
(4) =
63.9776gland)
* PROBLEMY (It's not 4.63 it's 4-15.49)
15.9994
63-99269_11688227-463
%
g derve
15.0.8256772g/mol
MAHARVARAPAREMATANDSVIN
(Okay hold on... AGAIN I don't understand.)
WIVAAAAM
www.w
hmm
C
100
2.745 15³1 A1₂ 504
=
convert to male, convert to mole, convert to mole convert to mole
7.
16882246
274
mand
4 moli
1 mol: A1² 504
150.0256772
que
to get close to the answer I can subtract 6.022 but
il must be setting it up wining.
43810
158.8256772.glimal 1 mal Al 504
4 mol: 0
do you... 2.74-1.168822746? I don't think 30
42.65776445%
.
why? I am
0-292205687
15.99949
1m610
n
6.2922 85687
2.74
↓
11.7998832% 0
50...
so lost.
175.353424
158.8256772
=
(180)
1.1168822746

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