Let f(x) = x - 6x² – 5, x 2 4.df-lat the point x = -30 = f(5).dxFind the value ofaGive your answer in the formb.the fraction is fully simplified.where a and b are positive integers anda 3=(Enter integers.)

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13 Let f(x) = x - 6x² – 5, x > 4. |-fp at the point x = -30 = f(5). Find the value of dx a Give your answer in the form where a and b are positive integers and the fraction is fully simplified. a = (Enter integers.) b =

13 Let f(x) = x - 6x² – 5, x > 4. |-fp at the point x = -30 = f(5). Find the value of dx a Give your answer in the form where a and b are positive integers and the fraction is fully simplified. a = (Enter integers.) b =

Big Ideas Math A Bridge To Success Algebra 1: Student Edition 2015

1st Edition

ISBN:9781680331141

Author:HOUGHTON MIFFLIN HARCOURT

Publisher:HOUGHTON MIFFLIN HARCOURT

Chapter8: Graphing Quadratic Functions

Section: Chapter Questions

Problem 16CT

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Limits

When it comes to calculus, limits are considered to be a very important topic of discussion. The main importance of limit lies in expressing the value of a function as it gets closer to a certain value. Also, limits can help you to understand other topics, such as continuity and differentiability better. In a broader sense, every calculus notion is a limit. Other branches of calculus have also been derived from limits.

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Let f(x) = x - 6x² – 5, x 2 4.
df-l
at the point x = -30 = f(5).
dx
Find the value of
a
Give your answer in the form
b.
the fraction is fully simplified.
where a and b are positive integers and
a 3=
(Enter integers.)

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