Answered: 13. Calculate the total electric flux…

13. Calculate the total electric flux through the paraboloidal surface due to a uniform electric field of magnitude E, in the direction shown in Figure P24.13. E, Figure P24.13

Physics for Scientists and Engineers

10th Edition

ISBN:9781337553278

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter23: Continuous Charge Distributions And Gauss's Law

Section: Chapter Questions

Problem 17P: (a) Find the net electric flux through the cube shown in Figure P23.17. (b) Can you use Gausss law...

See similar textbooks

Related questions

Q: 22.57 · (a) An insulating sphere with Figure P22.57 radius a has a uniform charge density p. The…

Q: A uniformly charged disk with radius R = 25.0 cm and uniform charge density σ = 8.90 ✕ 10−3 C/m2…

A: The expression for the electric field for uniformly charged disk.

Q: A uniformly charged disk with radius R = 45.0 cm and uniform charge density o = 8.10 × 10¬3 C/m²…

A: The expression for the electric field for uniformly charged disk,

Q: A positively charged rod of length L = 0.250 m with linear charge density λ = 2.33 mC/m lies along…

A: length L = 0.250 m linear charge density λ = 2.33 mC/m distance 0.375 m

Q: Assume the magnitude of the electric field on each face of the cube of edge L=2 m in the figure is…

Q: 9.) What is the electric flux passing through a Gaussian surface that contains two protons? A) 3.62…

Q: Rank the electric fluxes through each gaussian surface shown in Figure O Q24.11 from largest to…

Q: A thin rod of length ℓ and uniform charge per unit length λ lies along the x axis, as shown in…

A: Consider an elemental length 'dx' at a distance 'x' from the centre of the wire as shown in the…

Q: What is the electric field (in MN/C) due to the charged disk

A: Given data: The radius of disk is: R = 40 cm = 0.4 m The uniform charge density is: σ = 8.20×10-3…

Q: NOTE: Ke= 8.99x 10(power 9) N.m2/C2 A uniformly charged, straight filament 8 m in length has a total…

A: Given : ke = 8.99 × 109 N.m2/C2 L = 8 m q = 4 μC = 4 × 10-6 C ℓ = 4 cm = 0.04 m r = 12 cm = 0.12 m

Q: 21. A particle with charge Q is located a small dis- 8 immediately tance above the center of the…

A: partile with chage = Q distance = δ radius = R

Q: A uniformly charged disk with radius R = 35.0 cm and uniform charge density ? = 7.10 ✕ 10−3 C/m2…

Q: The figure below shows three charged particles arranged in the xy plane at the coordinates shown,…

Q: Careful measurement of the electric field at the surface of a black box indicates that the net…

A: Magnitude of Flux is given by Φo = 9.0 kN-m2/C εo = 8.854×10-12 C2/N-m2

Q: A uniformly charged disk of radius 35.0 cm carries charge with a density of a. If the electric field…

Q: conductor, what is the electric field at the center point O? O A. O B. O C. O D. Q = -3 [NC] 6 5п2€о…

Q: A uniformly charged disk with radius R = 25.0 cm and uniform charge density ? = 8.60 ✕ 10−3 C/m2…

Q: A positively charged rod of length L = 0.250 m with linear charge density λ = 2.33 mC/m lies along…

A: L = 0.250 m λ = 2.33 mC/m

Q: A uniformly charged disk with radius R = 45.0 cm and uniform charge density o = 8.10 × 10¬3 C/m²…

Q: A uniformly charged disk with radius R= 35.0 cm and uniform charge density a-8.40 x 10 C/m lies in…

A: Since you have posted a question with multiple sub-parts, we will solve the first three sub-parts…

Q: Ch 18, Problem 58 A charge Q is located inside a rectangular box. The electric flux through each of…

A: According to Gauss law, the total electric flux though a closed surface is directly proportional to…

Q: Assume the magnitude of the electric field on each face of the cube of edge L = 1.00 m in Figure…

A: Given: Length (L) = 1.00mFace Area (A) = 1 m2

Q: A uniformly charged disk with radius R = 45.0 cm and uniform charge density o = 6.50 x 10 C/m2 lies…

A: Given values: Radius of the disc, R=45.0 cm Charge density ,σ=6.50×10-3 C/m2 Permittivity of…

Q: Find the electric flux ( in units of N.m2/C) through the surface of the rectangle ( 30 cm x 40 cm)…

Q: Find the electric flux ( in units of N.m2/C) through the surface of the rectangle ( 30 cm X 40 cm)…

A: The given data are: E=332.8 N/CA=30 cm×40 cm=0.3 m×0.4 m=0.12 m2 Here, A denotes the plate area.

Q: There is a rectangle of length 2.70 cm and width 1.50 cm in the xy-plane. If the electric field can…

A: The electric flux through the rectangle is

Q: Find the electric flux ( in units of N.m2/C) through the surface of the rectangle ( 30 cm × 40 cm)…

Q: The electric field in a particular space is E→ = (x + 1.8)î N/C with x in meters. Consider a…

A: Electric flux through a closed surface is given by-ϕ=∮E.ds=Qenclosedε0

Q: Find the electric flux ( in units of N.m2/C) through the surface of the rectangle ( 30 cm x 40 cm)…

Q: A uniformly charged disk with radius R = 45.0 cm and uniform charge density o = 8.10 × 10¬3 C/m2…

Q: Careful measurement of the electric field at the surface of a black box indicates that the net…

Q: 17. An infinitely long line charge having a uniform charge per unit length A lies a distance d from…

A: a) R<d b) R>d here center is O length λ

Q: Assume the magnitude of the electric field on each face of the cube of edge L = 1.00 m as shown is…

A: The flux on each surface can be calculated as Where E is the electric field on each face and A is…

Q: Find the electric flux ( in units of N.m2/C) through the surface of the rectangle ( 30 cm X 40 cm)…

Q: 2. A disk of radius 196 mm is oriented with its normal unit vector în at 60° to a uniform electric…

Q: 7) A charge q = 2.00 µC is placed at the origin in a region where there is already a uniform…

A: Since a Gaussian surface in the form of a sphere at radius r, the electric field has a similar…

Q: A disk of radius r= 70 cm has a uniform surface charge density o= 62.1 nC. Calculate the electric…

Q: A flat surface of area 8 m^2 is rotated in a uniform electric field of magnitude E=3.20 x10^5 N/C.…

A: The electric flux through a surface is given by, ΦE = EAcosθ where E is the magnitude of the…

Q: 25.0 N/C 20.0 N/C. 20.0 N/C 35.0 N/C 20.0 N/C 15.0 N/C Assume the magnitude of the electric field on…

A: Data Given , Side of the cube ( L ) = 10.62 m From the given figure , The direction of Electric…

Q: A cylindrical shell of length 200 m and radius 8 cm carries a uniform surface charge density of o =…

Q: 32. Assume the magnitude of the electric field on each face of the cube of edge1.00 m in Figure…

A: a)First, we determine the area of each face of the cube. length of each side of the cube is given as…

Q: An electric field with a magnitude of 3.5 kN/C is applied along the x-axis. Calculate the electric…

A: Given Electric field=E=3.5 KN/C Electric field is along x axis width of rectangle plane =w=0.35 m…

Q: ++ + + b + + + A hollow sphere has a uniform volume charge density of 1.46 nC/m³. The inner radius…

A: ρ=1.46 nC/m3=1.46*10-9 C/m3a=11.7 cm = 0.117 mb = 46.8 cm =0.468 m

Q: A uniformly charged disk with radius R = 25.0 cm and uniform charge density o = 7.40 x 10-3 C/m2…

Q: 17. An infinitely long line charge having a uniform charge unit length A lies a distance d from…

Q: A disk of radius 0.10 m is oriented with its normal unit vector at 35° to the uniform electric field…

A: GivenRadius of disk ,r=0.1 mAngle ,θ=35°Magnitude of elctric field ,E=2.5 kN/C=2.5×103 N/C

Q: A non-conducting sphere with radius a = 4.0 cm is inside a conducting shell with radii b = 15.0 cm…

A: The radius of the non-conducting sphere, a=4.0 cm = 0.04 m The inner radius of the conducting…

Concept explainers

Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

Question

13. Calculate the total electric flux through the paraboloidal
surface due to a uniform electric field of magnitude E, in
the direction shown in Figure P24.13.
d
E,
Figure P24.13

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

(a) Find the net electric flux through the cube shown in Figure P23.17. (b) Can you use Gausss law to find the electric field on the surface of this cube? Explain. Figure P23.17
Assume the magnitude of the electric field on each face of the cube of edge L = 1.00 m in Figure P23.32 is uniform and the directions of the fields on each face are as indicated. Find (a) the net electric flux through the cube and (b) the net charge inside the cube. (c) Could the net charge he a single point charge? Figure P23.32
A solid insulating sphere of radius a = 5.00 cm carries a net positive charge of Q = 3.00 C uniformly distributed throughout its volume. Concentric with this sphere is a conducting spherical shell with inner radius b = 10.0 cm and outer radius c = 15.0 cm as shown in Figure P24.54, having net charge q = 1.00 C Prepare a graph of the magnitude of the electric field due to this configuration versus r for O r 25.0 cm.
Figure P15.49 shows a closed cylinder with cross-sectional area A = 2.00 m2. The constant electric field E has magnitude 3.50 103 N/C and is directed vertically upward, perpendicular to the cylinder's top and bottom surfaces so that no field lines paw through the curved surface. Calculate the electric flux through the cylinder's (a) lop and (b) bottom surface, (c) Determine the amount of charge inside the cylinder. Figure P15.49
A sphere of radius R surrounds a particle with charge Q located at its center as shown in Figure P23.43. Find the electric flux through a circular cap of half-angle . Figure P23.43
A solid, insulating sphere of radius a has a uniform charge density throughout its volume and a total charge Q. Concentric with this sphere is an uncharged, conducting, hollow sphere whose inner and outer radii are b and e as shown in Figure P24.45. We wish to understand completely the charges and electric fields at all locations. (a) Find the charge contained within a sphere of radius r a. (b) From this value, find the magnitude of the electric field for r a. (c) What charge is contained within a sphere of radius r when a r b? (d) From this value, find the magnitude of the electric field for r when a r b. (e) Now consider r when b r c. What is the magnitude of the electric field for this range of values of r? (f) From this value, what must be the charge on the inner surface of the hollow sphere? (g) From part (f), what must be the charge on the outer surface of the hollow sphere? (h) Consider the three spherical surfaces of radii a, b, and c. Which of these surfaces has the largest magnitude of surface charge density? Figure P24.45 Problems 43 and 47.
Find the net electric flux through (a) the closed spherical surface in a uniform electric field shown in Figure P23.22a and (b) the closed cylindrical surface shown in Figure P23.22b. (c) What can you conclude about the charges, if any, inside the cylindrical surface? Figure P23.22
aA plastic rod of length = 24.0 cm is uniformly charged with a total charge of +12.0 C. The rod is formed into a semicircle with its center at the origin of the xy plane (Fig. P24.34). What are the magnitude and direction of the electric field at the origin? Figure P24.34
Find an expression for the magnitude of the electric field at point A mid-way between the two rings of radius R shown in Figure P24.30. The ring on the left has a uniform charge q1 and the ring on the right has a uniform charge q2. The rings are separated by distance d. Assume the positive x axis points to the right, through the center of the rings. FIGURE P24.30 Problems 30 and 31.
Figure P15.49 shows a closed cylinder with cross-sectional area A = 2.00 m2. The constant electric field E has magnitude 3.50 103 N/C and is directed vertically upward, perpendicular to the cylinder's top and bottom surfaces so that no field lines paw through the curved surface. Calculate the electric flux through the cylinder's (a) lop and (b) bottom surface, (c) Determine the amount of charge inside the cylinder. Figure P15.49
Two infinite, nonconducting sheets of charge are parallel to each other as shown in Figure P24.56. The sheet on the left has a uniform sur- face charge density σ, and the one on the right has a uniform charge density -σ. Calculate the electric field at points (a) to the left of, (b) in between, and (c) to the right of the Figure P24.56 two sheets. (d) What If? Find the electric fields in all three regions if both sheets have positive uniform surface charge densities of value σ.
A flat square sheet of thin aluminum foil, 40 cm on a side, carries a uniformly distributed 355 nC charge. What, approximately, is the electric field 1.0 cm above the center of the sheet?Express your answer using two significant figures.