13. Silver bromide was prepared by reacting 200.0 g of magnesium bromide with an excessof aqueous silver nitrate solution according to the balanced equation below.a. How many grams of silver bromide could be produced?b. If 375.0 g of AgBr is actually collected, what is the percent yield?MgBr2(s) 2 AgNO3(aq)>Mg(NO3)(aq) 2 AgBr(s)

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Asked Oct 25, 2019
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13. Silver bromide was prepared by reacting 200.0 g of magnesium bromide with an excess
of aqueous silver nitrate solution according to the balanced equation below.
a. How many grams of silver bromide could be produced?
b. If 375.0 g of AgBr is actually collected, what is the percent yield?
MgBr2(s) 2 AgNO3(aq)
>Mg(NO3)(aq) 2 AgBr(s)
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13. Silver bromide was prepared by reacting 200.0 g of magnesium bromide with an excess of aqueous silver nitrate solution according to the balanced equation below. a. How many grams of silver bromide could be produced? b. If 375.0 g of AgBr is actually collected, what is the percent yield? MgBr2(s) 2 AgNO3(aq) >Mg(NO3)(aq) 2 AgBr(s)

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Expert Answer

Step 1

Given,

200.0 g of magnesium bromide.

The balanced equation is given below
MgBr (s)2AgNO,(aq)- MgNO,(aq) +2AgBrs)
Molar mass of magnesium bromide = 184.113 g/mol
Molar mass of silver bromide = 187.77 g/mol
According to the reaction, one mole of magnesium bromide gives two moles silver bromide.
Number of moles of magnesium bromide is calculated as follows,
Mass
Moles
Molar mass
200g
Moles
184.113g/mol
Moles 1.086
MgBr(s)2AgNO3(aq)-MgNO2(aq) + 2AgBr(s)
According to the reaction, one mole of magnesium bromide gives two moles silver bromide.
Number of moles of silver bromide is calculated as follows
Moles 2x1.086 mol
Moles 2.172 mol Ag Br
Number of moles of silver bromide is calculated
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The balanced equation is given below MgBr (s)2AgNO,(aq)- MgNO,(aq) +2AgBrs) Molar mass of magnesium bromide = 184.113 g/mol Molar mass of silver bromide = 187.77 g/mol According to the reaction, one mole of magnesium bromide gives two moles silver bromide. Number of moles of magnesium bromide is calculated as follows, Mass Moles Molar mass 200g Moles 184.113g/mol Moles 1.086 MgBr(s)2AgNO3(aq)-MgNO2(aq) + 2AgBr(s) According to the reaction, one mole of magnesium bromide gives two moles silver bromide. Number of moles of silver bromide is calculated as follows Moles 2x1.086 mol Moles 2.172 mol Ag Br Number of moles of silver bromide is calculated

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Step 2

Number of grams of silver bromide is calculated.

Number of grams of silver bromide is calculated as follows
Mass Moles x Molar mass
Mass 2.172mol x 187.77 g/mol
Mass 407.8 g
Number of grams of silver bromide is 407.8g
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Number of grams of silver bromide is calculated as follows Mass Moles x Molar mass Mass 2.172mol x 187.77 g/mol Mass 407.8 g Number of grams of silver bromide is 407.8g

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Step 3

Percent yield has to ...

Number of moles of magnesium bromide is calculated as follows
Mass
Moles
Molar mass
200 g
Moles
184.113 g/mol
Moles 1.086
Number of moles of silver bromide (2 moles) is calculated as follows
Mass
Moles
Molar mass
375 g
Moles
187.77 g/mol
Moles 1.997
Therefore, number of moles for one mole of silver bromide is given below
1.997
For one mole of silver bromi de=
2
For one mole of silver bromide-0.9985
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Number of moles of magnesium bromide is calculated as follows Mass Moles Molar mass 200 g Moles 184.113 g/mol Moles 1.086 Number of moles of silver bromide (2 moles) is calculated as follows Mass Moles Molar mass 375 g Moles 187.77 g/mol Moles 1.997 Therefore, number of moles for one mole of silver bromide is given below 1.997 For one mole of silver bromi de= 2 For one mole of silver bromide-0.9985

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