13..TeamDayDragonsSunday Swallows 4TigersSunday Bay Stars9CarpSunday NULLSwallowsSunday DragonBay Stars Sunday TigersGiantsSunday NULLMonday CarpDragonsTigersCarpOpponent RunsMonday NULLMonday DragonsSwallows Monday GiantsBay Stars Monday NULLGiants Monday Swallowsb)C)Considering the above table, what is the result of thefollowing query?d)NULL7SELECT S1.Team, S2.TeamFROM Scores S1, Scores S2WHERE S1.Opponent S2.Opponent ANDS1.Team S2.Team2Identify in the list below a tuple of the result.a)Bay StarsTigersCarpNULLNULLNULLNULL0GiantsGiantsNULL5CijantsDragonsBay Stars

Self join is a join which is used to join the table with itself showing that there exist two tables.

13. Team Dragons Tigers Carp Swallows Bay Stars Giants Dragons Tigers Carp Swallows Monday Giants Bay Stars Monday NULL Giants Opponent Runs Day Sunday SwallowS 4 Sunday Bay Stars 9 Sunday NULL Sunday Dragons Sunday Tigers Sunday NULL Monday Carp Monday NULL Monday Dragons SELECT S1.Team, S2.Team FROM Scores S1, Scores S2 b) C) d) Monday Swallows NULL 7 Considering the above table, what is the result of the . following query? 2 Carp NULL NULL WHERE S1.Opponent=S2.Opponent AND S1.Team S2.Team Giants Identify in the list below a tuple of the result. a) Bay Stars Tigers Giants NULL NULL 0 NULL 5 jants Dragons Bay Stars

13. Team Dragons Tigers Carp Swallows Bay Stars Giants Dragons Tigers Carp Swallows Monday Giants Bay Stars Monday NULL Giants Opponent Runs Day Sunday SwallowS 4 Sunday Bay Stars 9 Sunday NULL Sunday Dragons Sunday Tigers Sunday NULL Monday Carp Monday NULL Monday Dragons SELECT S1.Team, S2.Team FROM Scores S1, Scores S2 b) C) d) Monday Swallows NULL 7 Considering the above table, what is the result of the . following query? 2 Carp NULL NULL WHERE S1.Opponent=S2.Opponent AND S1.Team S2.Team Giants Identify in the list below a tuple of the result. a) Bay Stars Tigers Giants NULL NULL 0 NULL 5 jants Dragons Bay Stars

A Guide to SQL

9th Edition

ISBN:9781111527273

Author:Philip J. Pratt

Publisher:Philip J. Pratt

Chapter7: Database Administration

Section: Chapter Questions

Problem 4TD: Write, but do not execute, the commands to grant the following privileges: a. User Ashton must be...

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2.21 LAB - Create LessonSchedule table with FK constraints Two tables are created: Horse with columns: ID - integer, primary key RegisteredName - variable-length string Student with columns: ID - integer, primary key FirstName - variable-length string LastName - variable-length string Create the LessonSchedule table with columns: HorseID - integer with range 0 to 65 thousand, not NULL, foreign key references Horse(ID) StudentID - integer with range 0 to 65 thousand, foreign key references Student(ID) LessonDateTime - date/time, not NULL Primary key is (HorseID, LessonDateTime) If a row is deleted from Horse, the rows with the same horse ID should be deleted from LessonSchedule automatically. If a row is deleted from Student, the same student IDs should be set to NULL in LessonSchedule automatically
12.13 LAB - Select lesson schedule with multiple joins Hello, I need help on this sql query statement. Write a SELECT statement to create a lesson schedule for Feb 1, 2020 with the lesson date/time, student's first and last names, and the horse's registered name. Order the results in ascending order by lesson date/time, then by the horse's registered name. Make sure unassigned lesson times (student ID is NULL) appear in the results. Hint: Perform a join on the LessonSchedule, Student, and Horse tables, matching the student IDs and horse IDs. This is my database... Horse with columns: ID - primary key RegisteredName Breed Height BirthDate Student with columns: ID - primary key FirstName LastName Street City State Zip Phone EmailAddress LessonSchedule with columns: HorseID - partial primary key, foreign key references Horse(ID) StudentID - foreign key references Student(ID) LessonDateTime - partial primary key
2.14 LAB - Create LessonSchedule table with FK constraints Two tables are created: Horse with columns: ID - integer, primary key RegisteredName - variable-length string Student with columns: ID - integer, primary key FirstName - variable-length string LastName - variable-length string Create the LessonSchedule table with columns: HorseID - integer with range 0 to 65 thousand, not NULL, partial primary key, foreign key references Horse(ID) StudentID - integer with range 0 to 65 thousand, foreign key references Student(ID) LessonDateTime - date/time, not NULL, partial primary key If a row is deleted from Horse, the rows with the same horse ID should be deleted from LessonSchedule automatically. If a row is deleted from Student, the same student IDs should be set to NULL in LessonSchedule automatically.
3.8 LAB - Create LessonSchedule table with FK constraints Two tables are created: Horse with columns: ID - integer, primary key RegisteredName - variable-length string Student with columns: ID - integer, primary key FirstName - variable-length string LastName - variable-length string Create the LessonSchedule table with columns: HorseID - integer with range 0 to 65 thousand, not NULL, partial primary key, foreign key references Horse(ID) StudentID - integer with range 0 to 65 thousand, foreign key references Student(ID) LessonDateTime - date/time, not NULL, partial primary key If a row is deleted from Horse, the rows with the same horse ID should be deleted from LessonSchedule automatically. If a row is deleted from Student, the same student IDs should be set to NULL in LessonSchedule automatically. Note: Table and column names are case sensitive in the auto-grader.
4.9 LAB - Select employees and managers with inner join The Employee table has the following columns: ID - integer, primary key FirstName - variable-length string LastName - variable-length string ManagerID - integer Write a SELECT statement to show a list of all employees' first names and their managers' first names. List only employees that have a manager. Order the results by Employee first name. Use aliases to give the result columns distinctly different names, like "Employee" and "Manager". Hint: Join the Employee table to itself using INNER JOIN.
Create the Operations.Stock table with four columns:-- The stockid column of type int-- The opID column of type int that defines -- a foreign key constraint 'fk_ops' -- against the opID column in Operators table-- The unitprice column of type moneyThe discontinued column of type BIT that will take NULL and a constraint named 'def_disc' defines a default value of zero Define a named primary key constraint called pk_stock on the stockid column Why is this statements foreign key preventing me from doing this? -- Insert a row into the table with the values 1 for the stockid, 3 for the opID and 22.95 for the unitprice
Given the following tables, there is a university rule preventing a student from enrolling in a new class if there is an unpaid fine. Please write a table-level CHECK constraint to implement the rule. */ create table Course (CourseID int primary key, CourseName varchar(50), InstructorID int, AcademicYear int, Semester smallint); create table Student (StudentID int primary key, LastName varchar (50), FirstName varchar (50), Email varchar(30), PhoneNumber varchar (20)); create table Enrollment (CourseID int references Course(CourseID), StudentID int references Student(StudentID), RegisterDate date, primary key (CourseID, StudentID)); create table Fine (StudentID int references Student(StudentID), IssueDate date, Amount money, PaidDate date primary key (StudentID, IssueDate));
Problems 2224 are based on the following query: SELECT P_CODE, P_DESCRIPT, P_PRICE, P.V_CODE, V_STATE FROM PRODUCT P, VENDOR V WHERE P.V_CODE = V.V_CODE AND V_STATE = 'NY' AND V_AREACODE = '212' ORDER BY P_PRICE; Write the command(s) used to generate the statistics for the PRODUCT and VENDOR tables.
Write, but do not execute, the commands to grant the following privileges: a. User Ashton must be able to retrieve data from the ITEM table. b. Users Kelly and Morgan must be able to add new orders and order lines. c. User James must be able to change the price for all items. d. User Danielson must be able to delete customers. e. All users must be able to retrieve each customers number, name, street, city, state,and postal code. f. f User Pere7 must be able to create an index on the ORDFRS table. g. User Washington must be able to change the structure of the ITEM table. h. User Grinstead must have all privileges on the ORDERS table.
What is the difference between a PRIMARY KEY constraint and a UNIQUE constraint?
8. Create a trigger for the Invoices table that automatically inserts the vendor name and address for a paid invoice into a table named ShippingLabels. The trigger should fire any time the PaymentTotal column of the Invoices table is updated. The structure of the ShippingLabels table is as follows: CREATE TABLE ShippingLabels (VendorName varchar(50), VendorAddress1 varchar(50), VendorAddress2 varchar(50), VendorCity VendorState VendorZipCode varchar(50), char(2), varchar(20)); Use this UPDATE statement to test the trigger: UPDATE Invoices SET PaymentTotal = 67.92, PaymentDate = '2020-02-23' WHERE InvoiceID = 100;
Answer the given question with a proper explanation and step-by-step solution. In Design View of the DirectorSeptember query, add criteria using wildcard characters to select all records with Director anywhere in the JobTitle field and an ApplicationDate greater than or equal to 9/1/2018. Run the query to display it in Datasheet View as shown in Figure 3, and then save and close it.

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