13. What is the partial pressure of CO2 in an equilibrium decomposition process of CaCO at 750.0°C? CACO3(s) CaO(s) CO:(g) Given: Substance AHP (kJ/mol) S (J/K.mol) CACO3(s) -1206.9 CaO(s) -635.6 CO2(g) -393.5 92.9 39.8 213.6 A) 0.203 atm B) 0.535 atm C) 4.93 atm D) 0.0253 atm

Chemistry: Principles and Reactions
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ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
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Chapter12: Gaseous Chemical Equilibrium
Section: Chapter Questions
Problem 70QAP: For the reaction C(s)+CO2(g)2CO(g) K=168 at 1273 K. If one starts with 0.3 atm of CO2 and 12.0 g of...
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13. What is the partial pressure of CO2 in an equilibrium decomposition process of CaCO
at 750.0°C?
CaCO3(s) =
CaO(s)
CO:(8)
Given:
Substance
AHP (kJ/mol)
S (J/K.mol)
CACO3(s)
-1206.9
CaO(s)
-635.6
CO2(g)
-393.5
92.9
39.8
213.6
A) 0.203 atm
B) 0.535 atm
C) 4.93 atm
D) 0.0253 atm
Transcribed Image Text:13. What is the partial pressure of CO2 in an equilibrium decomposition process of CaCO at 750.0°C? CaCO3(s) = CaO(s) CO:(8) Given: Substance AHP (kJ/mol) S (J/K.mol) CACO3(s) -1206.9 CaO(s) -635.6 CO2(g) -393.5 92.9 39.8 213.6 A) 0.203 atm B) 0.535 atm C) 4.93 atm D) 0.0253 atm
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