13.58 The end of a cylindrical liquid cryogenic propellant tank in free space is to be protected from external (solar) radi- ation by placing a thin metallic shield in front of the tank. Assume the view factor F, between the tank and the shield is unity; all surfaces are diffuse and gray, and the surroundings are at 0 K. T Shield, T, T, = 100 K E1 = E2 = 0.05 &= 0.10 Ĝ; = 1250 W/m? %3D Tank Solar irradiation Gs

13.58 The end of a cylindrical liquid cryogenic propellant tank in free space is to be protected from external (solar) radi- ation by placing a thin metallic shield in front of the tank. Assume the view factor F, between the tank and the shield is unity; all surfaces are diffuse and gray, and the surroundings are at 0 K. T Shield, T, T, = 100 K E1 = E2 = 0.05 &= 0.10 Ĝ; = 1250 W/m? %3D Tank Solar irradiation Gs

Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)

8th Edition

ISBN:9781305387102

Author:Kreith, Frank; Manglik, Raj M.

Publisher:Kreith, Frank; Manglik, Raj M.

Chapter11: Heat Transfer By Radiation

Section: Chapter Questions

Problem 11.49P

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11.31 A large slab of steel 0.1 m thick contains a 0.1 -m-di- ameter circular hole whose axis is normal to the surface. Considering the sides of the hole to be black, specify the rate of radiative heat loss from the hole. The plate is at 811 K, and the surroundings are at 300 K.
11.68 Two infinitely large, black, plane surfaces are 0.3 m apart, and the space between them is filled by an isothermal gas mixture at 811 K and atmospheric pressure. The gas mixture consists of by volume. If one of the surfaces is maintained at 278 K and the other at 1390 K, calculate (a) the effective emissivity of the gas at its temperature, (b) the effective absorptivity of the gas to radiation from the 1390 K surface, (c) the effective absorptivity of the gas to radiation from the 278 K surface, and (d) the net rate of heat transfer to the gas per square meter of surface area.
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