131 Knots 295 185 5) 53 knols Brakes t Ftrest 185 82 Ft 4576ft V; = 131 lcnots/.gF 67.3922 mIs Ve= 53kneds /1.944= 27.2656 mls al braking d,=45764(3.281=1394.765 m 24.9936 m for 18s dz= 82 ft /3.281= az= brakiny + reverse thost br29 -18s lal=? la,1=? te= 29-18 1ls de =1394.765 + 24.9936 = 1L119.76m

131 Knots 295 185 5) 53 knols Brakes t Ftrest 185 82 Ft 4576ft V; = 131 lcnots/.gF 67.3922 mIs Ve= 53kneds /1.944= 27.2656 mls al braking d,=45764(3.281=1394.765 m 24.9936 m for 18s dz= 82 ft /3.281= az= brakiny + reverse thost br29 -18s lal=? la,1=? te= 29-18 1ls de =1394.765 + 24.9936 = 1L119.76m

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter30: Atomic Physics

Section: Chapter Questions

Problem 14CQ: CT scanners do not detect details smaller than about 0.5 Is this limitation clue to the wavelength...

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Concept explainers

Distance and Speed

The speed, distance and time relation forms the basis of study of motion. You will need these concepts in the study of Mechanics. This concept is applicable for students who are studying the following courses –

Question

A plane touches down with 4576 ft of runway and an 82 foot safety zone. The planes lands going 131 knots. It brakes for 18 sec before initiating reverse thrust for an additional 11 sec. After the total 29 sec the plane leaves the safety zone and hits a car. (Diagram)

What is the acceleration (a1) for the first 18 seconds?

What is the second acceleration (a2) for the 11 seconds?

131 Knots
295
185
5)
53 knols
Brakes t Ftrest
185
82 Ft
4576ft
V; = 131 lcnots/.gF
67.3922 mIs
Ve= 53kneds /1.944= 27.2656 mls
al
braking
d,=45764(3.281=1394.765 m
24.9936 m
for 18s
dz= 82 ft /3.281=
az= brakiny + reverse thost br29 -18s
lal=?
la,1=?
te= 29-18 1ls
de =1394.765 + 24.9936 = 1L119.76m

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