13x + 13 dx. (x+ 2)(x2 + 9) Question 4 Evaluate

Q: 13 Xy-2Y=x Sin (2x)-13x , Y(IT) = 13

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Q: १) ( +² (9-x²) 3/ dx

A: As per company guidelines we are allowed to solve one question at a time so i an solving one please…

Q: a-) I = c6 Vx²-9 dx 3 b-) S x In(x² + 1) dx

A: Note: Since you have asked multiple questions, we will solve the first question for you. If you want…

Q: (21 + V3)/3 11 dx Evaluate 50 + x - 14x

A: Explanation of the answer is as follows

Q: 8 3x -dx 3 3 V 2 – x 2 -

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Q: 3. f; 3x – 1 -dx J 25х? -16

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Q: tan(z) + V3 = 0

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Q: x²-x+1 -dx. Evaluate:

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Q: .2 x+3 Evaluate / -dx (x+1)(x²+1)

A: Given integral, ∫x2+3x+1x2+1dx

Q: 3/2 x+3/2 x² - 2 Show that dx = In 3.

A: Since there are multiple questions posted, we will answer the first question posted (4). If you want…

Q: (sin 2x-3 W4-x² dx Evaluate -2

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Q: -3* dx. Evaluate O2 3 3 +1

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Q: sin x xý + 3y += x2

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Q: 1 -dx x2 Evaluate 2 8.

A: ∫xndx=xn+1n+1+C

Q: (2х+3) dx (x2+3х-6)9

A: ∫2x+3(x2+3x-6)9dx=∫(x2+3x-6)-9 (2x+3) dxusing formula∫fn(x) f'(x)dx =fn+1(x)n+1+chere, f(x)=x2+3x-6…

Q: .4 -1 sec J2 Evaluate x dx

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Q: 5 dx. 2. Evaluate J-∞x²+25

A: “Since you have asked multiple question, we will solve the first question for you. If you want any…

Q: y=36 Areu S (36-2 -(6-x) dx 36 -x2 -(6-7) ठेx ニ

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Q: 3-x Evaluate I = . -dx Vx-2°

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Q: 2х -3 -dx. Evaluate(x-2)(x² + 1)

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Q: 2. Using trigonometric substitution, what is f- vx²-9 dx ?

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Q: (2х-1)dx х4-2х3+x2

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Q: x-3 dx x-6х+1 -2.

A: NOTE: Refresh your page if you can't see any equations. . multiply and divide by 2

Q: 3) dx Evaluate : J4x (x² - 3)° dx

A: Given that a integration and we solve by using general formula of integration. We know that…

Q: (sin (x/9)°dx J81-x? ral 2

A: First we put sin-1(x/9)=t and differentiate both side with respect to t and then solve it. Follow…

Q: ii) Evaluate 3 -dx . Hence, solve et 2e* -dx . + +2

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Q: 2-8x Evaluate dx. 49-4x

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Q: x(3-5х) J - (3x-1)(х-1)* # 2) Evaluate: -dx-

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Q: I. Power Formula sec² xdx 1. S (1–4tanx)7 (2x+1)dx (x+2)*(x-1)* 2. S;

A: In this question we have to find the following integral using power formula. We know, Power formula,…

Q: the origin 2 2 S (1-10²1) ² dx -1 2

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Q: 3- x 3) dx → S2xe* dx

A: To evaluate the given integrals.

Q: 2 x -dx 6. Jo 1-x

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Q: 6. f 2x³sin (3x) dx

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Q: x +3 b. dx x2 - 3х - 10 с. x³ In(x²)dx at LKnow Chart part 2

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Q: sin(2x3 +3y3) If f(x,y)= 5330x2+2665y2 (x,y)# (0,0) then (x,y)=(0,0)

A: Given,             fx,y=sin2x3+3y35330x2+2665y2x,y≠0,00x,y=0,0

Q: Evaluate the definite integral using the given values

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Q: 2. Evaluate. (Зx* - 2х + 1)dx -2

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Q: (a) f(x) dx = Enter an exact number only. 4 (b) |(4f(x) + 10x)dx = Enter an exact number only. 4

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Q: 16 / #(x²)dx if f(x)dx = 7. Find Enter the exact answer. xf (x² )dx = -4

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Q: (28 - 3х — х3) dx 3x - x) dx

A: Given,         ∫48x3dx=960 , ∫48xdx=24 , ∫48dx=4        The integral is : ∫4828-3x-x3dx

Q: 3x+5 Find S dx (Using substitution method). √3x-7

A: This question can be solved using the concept of integration by substitution.

Q: 2x Evaluate dx using suitable technique. (x² +4)(2x-1)

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Q: 3. (a) Determine 3 4 dx VI - x², + x2 (b) Determine 3 + V1- x2 4 dx 1+ x2

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Q: cosh 3 хр. 15) 1-sinh 3

A: Solution

Q: 18 (x² +9) (x+3) -dx

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Q: ppose f(x)= -cosx-4). Evaluate dx

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Q: 2 6* + dx i) 1-x²

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Q: (х2-2х+11)dx (x2+3х-4) .2.

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Q: (x5—6х4-2х2-Зx+4)dx Q2: х2+2

A: This question is based on simple integration

Q: 2 dx . 1- x Evaluate

A: The given integral is ∫02x1-xdx                       (1)