15 r= 5 - 10 sin 0

Q: 2 sin(8) + 1 = 0

A:

Q: Cos'8 Sin&0 Sin'o 2.

A:

Q: 10. (2 sin x + 3cos 2x)dx

A: As the policy of bartleby the provisions is to solve only one question at a time when

Q: 12 tan(0) = find sec(0) 12

A: sec(theta)=? cos(theta) = ?

Q: sin (7π/6) + cos (3π/2)

A: Given,

Q: 45. s 2 2 sin t -

A:

Q: 27. r = – 3(1 + sin 0)

A: Here by putting the value of theta we get r and plot the graph

Q: 1+ sin® (x*))* 8

A: Given: y = [1+ sin6(x8)]8

Q: 3. sin 0 1/2

A: Given, a)  sin(θ)=12b)  csc23π

Q: 39) Find sin é. y 5 12 13' 13

A:

Q: Solve the differential equations

A: Concept to  be used - We will be solving this differential equation using Integrating factor.Given…

Q: -sin 0 (b) 1 -sin 0| sin (0) – 1

A:

Q: 20 Y 2. Sin X 15 25

A:

Q: 5. y=2 sin 20; 0=0,0=

A:

Q: cos 2x-1 i) x sin 2x 2 tan 30–20 ii) tan 40

A: follow next step.

Q: - 4cos3 0 sin 0

A: To find the value of  -4cos30sin0

Q: 4 sin 0 1 – 3 cos 0

A: Using Pythagorean identity we write the equation with sin, then solve for sin theta.

Q: cos(8) – sin(0) = 1

A: cos(θ)- sin(θ)=1

Q: evaluate the integral

A:

Q: 7.) tan 0 sin 0 + cos0 = sec 0

A:

Q: (6 Sin (ix) dx

A:

Q: 0 1 (b) sin 3

A: To determine the value of the theta.

Q: (sin 20+1)d0 4. S sin²0+0

A: Given: I=∫(sin2θ+1)dθsin2θ+θ

Q: 6. f(1) =-e" sin (21 + 7 ) 3t -2t

A:

Q: Cos2 π/3 + sin2 π/3

A:

Q: 9=3 Sin 2X 2.

A: answer is in next step

Q: (b) . 2r sin- (2²) dr

A: We will use the method of substitution to solve the integral.

Q: 11. sin-(-0.99) 12. cos(-0.1)

A:

Q: 13. sin (x+ 77)° = cos (x –9)°

A: Given,  sin12 x+77°  = cosx-9°   We have to find the value of x.

Q: 1. sin 0 =

A: answer is in next step

Q: 1 sin x + 2 cos x + 3

A:

Q: 2+ sin 30 do 1 (b) / sec 0 tan 0 3 9 – 0²

A: To evaluate the given integral.

Q: 19. TT/2 -π/2 sin 0 de 20. * sec² 0 de

A: 19 ∫-π/2π/2 sinθdθ [-cosθ ]-π/2π/2 0 - 0 =0 other way sin is odd function so also integration is = 0…

Q: Solve the equation for 0 <0 < 2T = 4+ sin 0

A:

Q: f (1) =-e* sin (21 +1) 6.

A: The solution is given as

Q: 5x/6 sin(0) de

A: Given,

Q: 2 2. (sin cos x) = sin 2x +1 2х +

A: The given identity

Q: Solve the equation (2cos x - √3)(2 sin x - 1) = 0 on the interval [0, 2π).

A: To solve the equation 2cosx-32sinx-1=0 on the interval 0,2π. Solving the given equation.…

Q: 1. de 2-3 sin(0)

A:

Q: cos² 3ß – sin² 3ß

A:

Q: 12. x² sin(x + y) = 1, -

A:

Q: (4) sin 0 de 프2

A: Kindly go through the solution and let me know in case of any doubt or further clarification in the…

Q: (2л — 5)sin(4a)da - 8

A:

Q: ii) у" +у' — 6у%3 sin2x.

A:

Q: 5 sin(50) sin(0) dê

A: The given integral is ∫5sin5θsinθdθ.

Q: sin 0 35. r = cos 0 – 1

A: since you have asked multiple questions in single request so we will be answering only first…

Q: 20 csc(0) = 9 find sin(0).

A:

Q: ∫ sin^3 2θ (√cos 2θ ) dθ

A: Integrate∫sin32θcos2θdθ  ..........1

Q: | sin(2x) 2) +c 2 + cos(2x) da 2

A:

Q: 13. sin 0 = -0.71; 270° < 0< 360°

A: Let's analyze the graph of sin x If we get a angle in negative we can get the desired angle by 360…