150V t=0 iR ic + 5 mH 200 n3 vc(t) 20 nF7 Fig.Q2 The switch in the circuit of Fig.Q2 has been opened for a long time and is closed at 1= 0. Analyse the circuit to find
150V t=0 iR ic + 5 mH 200 n3 vc(t) 20 nF7 Fig.Q2 The switch in the circuit of Fig.Q2 has been opened for a long time and is closed at 1= 0. Analyse the circuit to find
Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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Question
![300 N
150V
t=0
i
iR
ic
5 mH
200 N3
20 nF Vc(t)
Fig.Q2
The switch in the circuit of Fig.Q2 has been opened for a long time and is closed at t 0.
Analyse the circuit to find
i)
ii)
the voltage across the capacitor, ve(t) for t2 0.
the current flowing through the inductor iL(t) for t20.
Appendix for Question 2
Damping
Natural Response Equations
Coefficient Equations
Overdamped
x(1) - Aje + Aze
x(0) - A, + Azi
dx/dr(0) - Ajs, + Asz
Underdamped
x(1) - (B, cos wt + B, sin a e
x(0) - B:
dx/dt(0) - -aB + waB2.
where w,- Va - a
Critically damped
x(1) - (D + D)e
x(0) - Dz.
dx/dr(0)
D- a D
Damping
Step Response Equations
Coefficient Equations
Overdamped
x(1) = X, + Aj e + Ase
x(0) = X, + Aj + A:
dx/dt(0) = Aj s1 + As s2
Underdamped
x(t) = X, + (Bị cos aat + B sin eaf et
x(0) = X, + Bị :
dx/dt(0) = -aB + aB
Critically damped
x(1) = X + Di tet + Det
x(0) = X, + D:
dx/dt(0) = D - «D
where X, is the final value of x(t).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd411f108-fdc7-4cf3-8b97-60ef4a2d1f01%2F9c7d8749-5003-4398-abfd-11f4fe6feec8%2F9sgc93g_processed.jpeg&w=3840&q=75)
Transcribed Image Text:300 N
150V
t=0
i
iR
ic
5 mH
200 N3
20 nF Vc(t)
Fig.Q2
The switch in the circuit of Fig.Q2 has been opened for a long time and is closed at t 0.
Analyse the circuit to find
i)
ii)
the voltage across the capacitor, ve(t) for t2 0.
the current flowing through the inductor iL(t) for t20.
Appendix for Question 2
Damping
Natural Response Equations
Coefficient Equations
Overdamped
x(1) - Aje + Aze
x(0) - A, + Azi
dx/dr(0) - Ajs, + Asz
Underdamped
x(1) - (B, cos wt + B, sin a e
x(0) - B:
dx/dt(0) - -aB + waB2.
where w,- Va - a
Critically damped
x(1) - (D + D)e
x(0) - Dz.
dx/dr(0)
D- a D
Damping
Step Response Equations
Coefficient Equations
Overdamped
x(1) = X, + Aj e + Ase
x(0) = X, + Aj + A:
dx/dt(0) = Aj s1 + As s2
Underdamped
x(t) = X, + (Bị cos aat + B sin eaf et
x(0) = X, + Bị :
dx/dt(0) = -aB + aB
Critically damped
x(1) = X + Di tet + Det
x(0) = X, + D:
dx/dt(0) = D - «D
where X, is the final value of x(t).
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