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16° to the horizontal. Its initial A block is sliding down a ramp at an angle of speed is 2.8 m/s. After sliding 13.6 m along the ramp, it comes to a rest. What is the coefficient of kinetic friction, uk, between the block and the ramp? Ө

16° to the horizontal. Its initial A block is sliding down a ramp at an angle of speed is 2.8 m/s. After sliding 13.6 m along the ramp, it comes to a rest. What is the coefficient of kinetic friction, uk, between the block and the ramp? Ө

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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A block is sliding down a ramp at an angle of 0 = 16° to the horizontal. Its initial speed is 2.8 m/s. After sliding 13.6 m along the ramp, it comes to a rest. What is the coefficient of kinetic friction, µ., between the block and the ramp? Ө
Transcribed Image Text:A block is sliding down a ramp at an angle of 0 = 16° to the horizontal. Its initial speed is 2.8 m/s. After sliding 13.6 m along the ramp, it comes to a rest. What is the coefficient of kinetic friction, µ., between the block and the ramp? Ө
imgsing-5 " " " f= = = ma =D₂ 0 = (2₁8nd1/²³ - 2x4x1333 13.6m a = 7.84 m/s 2 2 = vi ²-2 as 2x 13.6m = 0.29 m/ = 2.41M15 acceleration perpendicular to the ram And there is no : N₂ my cos & mg sine - lin N = ma mg my sin 6 Мкт MK mg cost = ma gsine - Ming cost = 9 мнд Given 0 = 16 9.8 m/s ² x sin 16° 2 x sin 16° - MK x 9.8 m/s ² x cos 16° = 0.29 m/s ² 2.7 mis- 0.29mis" un x 9.42 UK мк = UK 9.4241=√10. 256.
Transcribed Image Text:imgsing-5 " " " f= = = ma =D₂ 0 = (2₁8nd1/²³ - 2x4x1333 13.6m a = 7.84 m/s 2 2 = vi ²-2 as 2x 13.6m = 0.29 m/ = 2.41M15 acceleration perpendicular to the ram And there is no : N₂ my cos & mg sine - lin N = ma mg my sin 6 Мкт MK mg cost = ma gsine - Ming cost = 9 мнд Given 0 = 16 9.8 m/s ² x sin 16° 2 x sin 16° - MK x 9.8 m/s ² x cos 16° = 0.29 m/s ² 2.7 mis- 0.29mis" un x 9.42 UK мк = UK 9.4241=√10. 256.
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