16. A physics student rides a moped for 1 hour going 30 mph, then spends 1.5 hours not moving, and finally travels for another 2.0 hours going 30.0 mph. What is the student's average speed for the trip?

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Chapter1: Units, Trigonometry. And Vectors
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I need help with this question and understanding it (Not grading) (Not honor class)
Average Speed =
Overall Distance / Total Time
d/t
units = m/s
16. A physics student rides a moped for 1 hour going 30 mph, then spends 1.5 hours not
moving, and finally travels for another 2.0 hours going 30.0 mph. What is the student's
average speed for the trip?
Solving for
Speed
Equation
speed
= distance/time
Substitute (work) 30 +0 + (2) 30 =
1 + 1.5 + (2) 30 =
Answer with units
888
F3
DII
DD
F4
F5
F6
F7
F8
F9
F10
F11
%23
2$
&
*
2
7
Y
U
* 00
W/
Transcribed Image Text:Average Speed = Overall Distance / Total Time d/t units = m/s 16. A physics student rides a moped for 1 hour going 30 mph, then spends 1.5 hours not moving, and finally travels for another 2.0 hours going 30.0 mph. What is the student's average speed for the trip? Solving for Speed Equation speed = distance/time Substitute (work) 30 +0 + (2) 30 = 1 + 1.5 + (2) 30 = Answer with units 888 F3 DII DD F4 F5 F6 F7 F8 F9 F10 F11 %23 2$ & * 2 7 Y U * 00 W/
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