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JUST QUESTION 16 PLEASE
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- Repeat Example 5 when microphone A receives the sound 4 seconds before microphone B.Olympic Pole Vault The graph in Figure 7 indicates that in recent years the winning Olympic men’s pole vault height has fallen below the value predicted by the regression line in Example 2. This might have occurred because when the pole vault was a new event there was much room for improvement in vaulters’ performances, whereas now even the best training can produce only incremental advances. Let’s see whether concentrating on more recent results gives a better predictor of future records. (a) Use the data in Table 2 (page 176) to complete the table of winning pole vault heights shown in the margin. (Note that we are using x=0 to correspond to the year 1972, where this restricted data set begins.) (b) Find the regression line for the data in part ‚(a). (c) Plot the data and the regression line on the same axes. Does the regression line seem to provide a good model for the data? (d) What does the regression line predict as the winning pole vault height for the 2012 Olympics? Compare this predicted value to the actual 2012 winning height of 5.97 m, as described on page 177. Has this new regression line provided a better prediction than the line in Example 2?The equation of the regression line between two variables x (independent variable) and y (dependent variable) is given by y^=−3x+2; and the correlation coefficient is r=−.95. The possible x-values range from 1 to 10. Based on the given r, which of the following conclusions may be made? x and y are moderately correlated, and y tends to increase as x is increased. x and y are strongly correlated, and y tends to increase as x is increased. x and y are very weakly correlated. x and y are strongly correlated, and y tends to increase as x is decreased. There is no way to tell the relationship between x and y.
- Q1 - Returns on stocks X and Y are listed below: Period 1 2 3 4 5 6 7Stock X 6% 5% -2% 10% 3% 8% -4%Stock Y 11% 7% 10% -2% 3% 5% -1% What is the correlation of returns on the two stocks?Please round your answer to the nearest hundredth.Note that the correct answer will be evaluated based on the full-precision result you would obtain using Excel.Suppose that you run a correlation and find the correlation coefficient is 0.421 and the regression equation is ˆy=2.2x+6.96y^=2.2x+6.96. The center of your x-data was 5.2 and the center of your y-data was 18.6.If the critical value is .396, use the appropriate method to predict the yy value when xx is 6.8The value of correlation coefficient between variables X and Y lies between:A. 1 and 2B. 0 and 1C. -1 and +1D. -1 and 0
- If the value of Cronbach’s alpha is 0.07, it means ___________; a. Research instrument is not reliable b. Research instrument is internally consistent c. Data is reliable d. Data is internally consistentYou run a regression analysis on a bivariate set of data (n=87n=87). With ¯x=75.8x¯=75.8 and ¯y=26.4y¯=26.4, you obtain the regression equationy=−3.905x−60.301y=-3.905x-60.301with a correlation coefficient of r=−0.15r=-0.15. You want to predict what value (on average) for the response variable will be obtained from a value of 70 as the explanatory variable.What is the predicted response value? y =A random sample of nonindustrialized countries was selected, and the life expectancy in years is listed for both men and women. Men 61.7 42.8 72.6 57.9 55.4 62.1 Women 50.4 74.2 75.3 75.4 49.1 65.2 The correlation coefficient for the data is =r−0.003 and =α0.05. Should regression analysis be done? Now Find the equation of the regression line. Round the coefficients to at least three decimal places. =y′+abx =a =b Now Find women's life expectancy in a country where men's life expectancy =60 years. Round your answer to at least three decimal places. Women's life expectancy is ____ years.