160 t= 0 0.5 H Vo 312.5 pF 3 s a) IR(S) = a + 200 s + 6400 R = 16 N, L = 0,5 H, C = 312,5 µF b) Ig(s) = 0,1875 s- 6 s+200 s+6400 Vs(t)= 4 V Vc(t) =Vo(t) ic(t) V(t) i,(t) VR(t) ig (t) Constant voltage source voltage across capacitor 0.25 s+ 56 s+ 1600 s(s + 200 s + 6400 ) current through the capacitor c) I(s) = Voltage from inductance Inductance current Voltage across the resistor 0,0625 s+ 50 s+1600 3 (s)"1 (P s(s + 200 S+ 6400) Current flowing through the resistor Ve (0) = 3 V Capacitor voltage at time 1-0 R00 25600 e) 1(s) = After the switch has been open long enough, it is closed at t=0. Find the laplace transform of the current IR(t). M +200S+ 6400

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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160
t= 0
0.5 H
312.5 µF
3 s
a) IR(s) =
s +200 s + 6400
R = 16 N,
L = 0,5 H,
C = 312,5 µF
b) IR(s) =
-0,1875 s- 6
s+200 s+ 6400
Vs(t) = 4 V
Vc(t)= Vo (t)
ic(t)
V(t)
i,(t)
VR(t)
ig (t)
Constant voltage source
voltage across capacitor
0.25 s+ 56 s+ 1600
%3D
current through the capacitor
c) IR(s) =
Voltage from inductance
s(s +200 s + 6400)
Inductance current
Voltage across the resistor
0,0625 s+ 50 s +1600
S(s+200 s+ 6400)
Current flowing through the resistor
d) IR(s) =
Vc (0) = 3 V
Capacitor voltage at time 1-0
2+800 s +25600
e) IR(s) =
After the switch has been open long
enough, it is closed at t=0. Find the
laplace transform of the current IR(t).
s + 200 +6400
Transcribed Image Text:160 t= 0 0.5 H 312.5 µF 3 s a) IR(s) = s +200 s + 6400 R = 16 N, L = 0,5 H, C = 312,5 µF b) IR(s) = -0,1875 s- 6 s+200 s+ 6400 Vs(t) = 4 V Vc(t)= Vo (t) ic(t) V(t) i,(t) VR(t) ig (t) Constant voltage source voltage across capacitor 0.25 s+ 56 s+ 1600 %3D current through the capacitor c) IR(s) = Voltage from inductance s(s +200 s + 6400) Inductance current Voltage across the resistor 0,0625 s+ 50 s +1600 S(s+200 s+ 6400) Current flowing through the resistor d) IR(s) = Vc (0) = 3 V Capacitor voltage at time 1-0 2+800 s +25600 e) IR(s) = After the switch has been open long enough, it is closed at t=0. Find the laplace transform of the current IR(t). s + 200 +6400
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