-17 4x-8=9-.6x | 17 T

Q: (In(r))² 9. dr

A:

Q: 2(3y-5)=34

A: We will see the ans in next step

Q: Subtract 9x²y 3x? – 5 from the sum of -6xy - x - 1 and 5x?y? + 2x? – 1. 2,,2 |

A: First, find the sum of the polynomials -6x2y2-x2-1   and  5x2y2+2x2-1 Then,…

Q: (6.47) (T4)-(r-3.6)

A:

Q: y 2 -27 27 6 -8E 2.

A:

Q: 6x2 + 3y2 = c 6x + 3yy' = 0 у 3 5 when х - 4

A:

Q: Find the area of the unbounded shaded region.

A: The area is from -∞ to ∞ So the area is given by:

Q: Between z= -2.42 and z=-1.77

A: We have to find area Between z= -2.42 and z=-1.77

Q: Find 24e-5s 82 – 9 s2 + 8s + 17

A:

Q: s(t) = 1/t^3;  (-6 , -1/216) s'(6)= ?

A: Given: s(t)=1t3−6<t<−1216s'(6)=?

Q: -3.14-2z z=4.12

A: Evaluating -3.14-2z :

Q: (b): Evaluate: (8t³ – 9t² + 10)dt

A:

Q: y= [x]; for -3 sxS3 6. y=x-[x]; for -2 SxS2

A: Function y=x is the greatest integer function where -3≤x≤3 x=-3, -3≤x<-2-2, -2≤x<-1-1,…

Q: 2(3q-9)=9-3q

A:

Q: x' = 2 -1 6 7 where (0) -[] = 6

A: To solve the following system of differential equations

Q: 0.7x-11=3.5x-25

A: 0.7x-11=3.5x-25Taking all the x-terms on the left-hand side and the other terms on the right-hand…

Q: (a®j3 (7а)? 2 (-3a*)³ 3 3

A: The explanation of answer as follows

Q: O- - 1 2x (In x)2

A:

Q: 3 6) y=--x-1

A:

Q: a) (4+j3)(6-j8). (3切3)-(2ガ3)

A: By Bartleby policy I have to solve only first one as these are unrelated problems.These are…

Q: 5 -2s2-3s+4- L-¹1-

A: We will use Laplace transformation table to find inverse Laplace transformation of given function

Q: X+y=ロメ 4--(メ-リ (X-1)

A:

Q: 6. + 6x) + (In x - 2)y' = 0

A: Given : yx+6x+(lnx-2)y'=0

Q: (q/q-3) + 1 = (2/2q+1)

A: To solve for q, firstly, we take l.c.m on left hand side of equation.

Q: (x– 3) - ? = ? 5. For x2 # 9, x' -9

A: Given Data: Expression: x-32x2-9 Condition: x2≠9

Q: 9x |_the_r-ne S 9x - - 9xdx

A:

Q: 12) x - y> 2

A: To graph x-y>2

Q: 3 – x if 5x - 3 if I > 1

A:

Q: y = -6x - 12 2x – 2y = 10 (-6, 1) (1, -6) (-3, -6) (-1, -6) YA 7:51

A: Answer and explanation is given below...

Q: Q5/ Find A-в, if: 1 2 3 - 2 1 B = 2 A = 2 -1 0 1 3 - 1

A:

Q: 1ン ーr-- 1-

A:

Q: Q(s) = 5s³-28s2 +658+8 (s2+4) (s²-6s+13)

A:

Q: -24 = x - (-2) X= ?

A:

Q: y 21 14 가 + x 21 -21 -14 -7 14 -가 -14

A:

Q: 3. (x +2 ) Ex²-4)

A: y=(x+2)3x2-4

Q: Is -1 greater than -4

A: Integer type

Q: -1 r + 3 1 x + 3 5 * + 3

A:

Q: (-2,4) y 2 у = 4 − x2 -

A:

Q: 2x when x = 12 and y = -3

A: Given expression 2xy

Q: -1 2s-3 9s2-12s+20

A: Given, L-12s-39s2-12s+20 Expanding the given function as, L-129·s-23s-232+169-527L-11s-232+169

Q: 12. x+3y = 15 4x + y = 6 (3,-6)

A:

Q: X - (-8) = 16 X= ?

A: Given that  X-(-8) =16 Then we have to find value of x.  So now..  X-(-8) =16 X+8=16 X=16-8 X=8

Q: (a) |r – 5| – 2 + 3x if r < 5

A: Definition used -           For absolute value of x , We can write -

Q: Find () - (-) 24e-5s L-1 s2 – 9 s2 + 8s + 17

A: Laplace transform

Q: X+5-3 exs=! im メー4 47

A: We have to evaluate the limit of the above function.

Q: sx² – 21x – 20 - +*-4)? A x + 4 B. X - 4 (x + 4)(x – 4)² (x – 4)²

A:

Q: -2 -4 4 - om

A:

Q: > an-1(x – 2)" + - na,(x – 2)"+1 n=1 n=0

A:

Q: y=/8x -x? on

A:

Q: (- 4, - T< 4, 0<x

A: