17.37 PRACTICE: Vectors**: Longest sequence C++ A common statistic of interest is the longest sequence of some pattern in a list of items. For example, in football, one may be interested in the longest sequence of consecutive complete passes. Given a list in which each item is either the letter "I" (for an incomplete pass) or a number (for a completed pass), output the length of the longest sequence of complete passes. The list is preceded by the number of items. Given 8 4 15 9 I 30 2 I 20, the output is 3 (because the longest sequence of complete passes is 4 15 9). Hints: Use two variables, one that keeps track of the current sequence length, and another for the longest sequence length. In a for loop that iterates through the vector, if you see an "I", set the current sequence length to 0. Otherwise, you are in sequence (either at the beginning or later in the sequence), so increment the current sequence length. A simple way to compute the longest sequence is to potentially update that variable every time you update the current sequence length. Check if the current is greater than the longest -- if so, update the longest. When done iterating, just output the value of the longest sequence length variable. Please answer in c++ #include #include #include using namespace std; int main() { int numItems; vector listItems; string currItem; int i; // Get items cin >> numItems; for (i = 0; i < numItems; ++i) { cin >> currItem; listItems.push_back(currItem); } /* Type your code here */ return 0; }
17.37 PRACTICE: Vectors **: Longest sequence C++
A common statistic of interest is the longest sequence of some pattern in a list of items. For example, in football, one may be interested in the longest sequence of consecutive complete passes. Given a list in which each item is either the letter "I" (for an incomplete pass) or a number (for a completed pass), output the length of the longest sequence of complete passes. The list is preceded by the number of items. Given 8 4 15 9 I 30 2 I 20, the output is 3 (because the longest sequence of complete passes is 4 15 9).
Hints:
-
Use two variables, one that keeps track of the current sequence length, and another for the longest sequence length.
-
In a for loop that iterates through the vector, if you see an "I", set the current sequence length to 0.
-
Otherwise, you are in sequence (either at the beginning or later in the sequence), so increment the current sequence length.
-
A simple way to compute the longest sequence is to potentially update that variable every time you update the current sequence length. Check if the current is greater than the longest -- if so, update the longest.
-
When done iterating, just output the value of the longest sequence length variable.
Please answer in c++
#include <iostream>
#include <vector>
#include <string>
using namespace std;
int main() {
int numItems;
vector<string> listItems;
string currItem;
int i;
// Get items
cin >> numItems;
for (i = 0; i < numItems; ++i) {
cin >> currItem;
listItems.push_back(currItem);
}
/* Type your code here */
return 0;
}
Trending now
This is a popular solution!
Step by step
Solved in 2 steps
