19. Supposethat the normalunit vector N of a surface S at z = f(x,y) is determined, how does the denominatorupon solving for the normal vector get cancelled out? A. ds = dA B. ds = x? + y² dA C. ds = )? + (,) +1 dA D. ds = 1

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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19. Supposethat the normal unit vector N of a surface S at z = f(x,y) is determined, how does the denominatorupon solving
for the normal vector get cancelled out?
A. ds = dA
B. ds = x? + y2 dA
ds = JG)? + (f,)+1 dA
C.
D. ds = 1
20. Stoke's Theorem
A. cannot be used as a substitute to find the line integral.
B. will require the determination of a normal unit vector.
C. as a line integral can be solved using its differential form.
D. can be regarded both as a surface integral and line integral.
Transcribed Image Text:19. Supposethat the normal unit vector N of a surface S at z = f(x,y) is determined, how does the denominatorupon solving for the normal vector get cancelled out? A. ds = dA B. ds = x? + y2 dA ds = JG)? + (f,)+1 dA C. D. ds = 1 20. Stoke's Theorem A. cannot be used as a substitute to find the line integral. B. will require the determination of a normal unit vector. C. as a line integral can be solved using its differential form. D. can be regarded both as a surface integral and line integral.
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