19.335 #2 N₁ und #5 02 sd 21.35 N1G) + 120297 M₂03 (5) initial ander temps 27.45°< Finglater tap 24.63% Calculate AHF Shen MASS OF GLORter 6000g SPOF GLORter 0.44) MASS OF LATER je 120009 SPrster N 4.18-1/8.5
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- Convert 370 ppm of CO2 to μg/m3 at 20oC and 101.325 kPa. Convert 80 μg/m3 of SO2 to ppm at 25oC and 101.325 kPa.The pKw of ammonia in water varies with temperature as follows :θ/°C 10 15 20 25 30 35pKw 4.798 4.782 4.767 4.759 4.740 4.733Deduce as much information as you can from these values.e following relation describes the volume change in a water (solvent – species 1) and salt (solute – species 2) solution: V=1.001+16.625n2 +56.092 n23/2 +119.4n22 where V is expressed in units of liters, and n2 in kmole. (1) Obtain an expression for partial V2 in terms of n2, and determine partial V2 when x2 is approching 0 in liter per kmole. (2) Obtain an expression for partial V1 one in terms of n2, and one in terms of x1
- Ammonia (considered to be ideal gas, 1 mole) initially at 25 oC and 1 bar pressure is heated at constant pressure until the volume has tripled.Use CP = 25.895 + 32.999 x 10^– 3 T – 30.46 x 10^– 7 T2 , J/mole-KCalculate: c) delta H d) delta U e) delta S show complete solutionWhat would (triangle) Hrxn be for this new situation with 40 ml of both 1.0 M NaOH and 1.0 M HCl, Ccal=166.8, Tempertre final was 28.9 C, the initial temperature was 22.1 C.What is the mole fraction of magnesium nitrate, Mg(NO3)2, in an aqueous solution that is 5.549 wt % in magnesium nitrate? MW(Mg(NO3)2) = 148.315 g/mol. 5.834e-2 1.721e-1 7.080e-3 9.929e-1
- The weight fraction of methanol in an aqueous solution is 0.64. The mole fraction of methanol (x) satisfies a. X < 0.5 b. 0.5 < XM < 0.64 c. xu = 0.5 d. Xu ~ 0.5Aniline, C6H5NH2, and hexane, C6H14 , form partially miscible liquid - liquid mixtures at temperatures below 69. 1 °C. When 42.8 g of aniline and 75 .2 g of hexane are mixed together at a temperature of 67.5 °C, two separate liquid phases are formed, with mole fractions of aniline of 0.308 and 0.618.(a) Determine the overall mole fraction of aniline in the mixture. (b) Use the lever rule to determine the relative amounts of the two phases.A 3 m^3 drum contains a mixture at 101 KPa and 35 C of 60% Methane (CH4) and 40% oxygen (O2) on a volumetric basis. a. Determine the amount of oxygen that must be added at 35 C to change the volumetric analysis to 50% of each component.
- Aniline, C6H5NH2, and hexane, C6H14, form partially miscible liquid–liquid mixtures at temperatures below 69.1 °C. When 42.8 g of aniline and 75.2 g of hexane are mixed together at a temperature of 67.5 °C, two separate liquid phases are formed, with mole fractions of aniline of 0.308 and 0.618. (i) Determine the overall mole fraction of aniline in the mixture. (ii) Use the lever rule to determine the relative amounts of the two phases.An experiment was conducted to determine the effect of glucose on the freezing point of water. Experimental data showed thatthe freezing point depression of water in solution was –2.6°C when 1.0 g of glucose was dissolved in 10g of solvent. Calculatethe expected freezing point for such solution and compare the expected freezing point to the value found experimentally. Give aplausible explanation for any discrepancies. (M.W. of glucose= 180.16g/mol; i=1). Show all your work.solve as neatly as possible and show completesolution. Round your final answer to 4 decimal places and box / highlight all final answers. and all values must include proper units with proper conversion if needed in your solution. kindly folllow the format Given,Required,Solution subject physical chemistry 1. Calculate the mass of water vapor present in a room of volume 400 m3 thatcontains air at 290C when the relative humidity is 53.0%. Compute for the vaporpressure of water?