1C=14x+5y Subject to X+2yc=16 2x+y>=16 2x+2y=24 X.y>=0

Q: Show that the equations x+ y +z = 4, 2x + 5y - 2z = 3, x + 7y - 7z = 5 are not consistent.

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Q: 1. 3x²y²dx + ( 2x³y + x ³y 4) dy =0, when x=2, Y= 3

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Q: x + 2y +32 = -1 - 2 + 5y +7z=5 +3₂ = 5 32 4y 2. X+Y-2=3 Sx - 2y + 2 = 8 x + 3y + 4z = 5 1.

A: To find the solution of the linear equations (1) x+2y+3z=−1   ...(a) −z+5y+7z=5 ⇒5y+6z =5…

Q: General solution of 2xydx+y^2dy=0

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Q: to d. 1 2/3 60% 4 61° °, mz2 = °, mz3 = %3D mz1 =

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Q: Solve y′′ + 4y = u2(t), y(0)=1, y’(0)=2

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Q: Solve: xy + y + 4x³y¹ = 0 O 6ry³ + Cr³y³ = 1 O 15r y³ +Cr³y³ = 4 O9r³y³ + Cr³y³ = 5 O 2r³y³ + Cr³y³…

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Q: Show that y = ex + 3xex  is a solution of y"-2y'+y=0

A: The given differential equation is,

Q: S 4x -Ry +32 = -2 2x +2y + Sz = 15 X+2y+3z=-3 -1x ty-2= 6 ! 3x-3y +22 = -4 ち=えも-s-x8 14+3x+2< 4y-2x…

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Q: 4 (a) s(-) = -2x + -4x +3x (b) s(<) = 2x° + (c) s(2) = -2(x - 2) (*+ 4) %3D 2.

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Q: Solve Ytt = = 4yxx 0 0 Yx(0, t) = 0, Yx(1, t) = 0, Y (x, 0) = 0, y(x, 0) = 3cos(2nx)

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Q: Start 2х - Зу - 10 y= -2x + 2 2x + y = 6 x+y- 8 yx+6 2x - y = 4 x+ y- 2 (7,1)} (1,2)} {(2,1)} x+ y-…

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Q: Solve by Graphical Method Max z=2x+4y Subjected to 3x+4y0

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Q: + 3 satisfies (1– x² )y"-2 xy'+20 y = 0.

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Q: (b) x' = -x – 3y + 2z + yz, y' = 3x – y – z + xz, z' = -2x + y – z + xy.

A: As per your query the solution of the part (b) has been done in detail in the following steps.

Q: 2. / Vy² – 4y + 10 dy

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Q: with solution Final dy वर di dr-/2cset-1 de lesct. +2

A: We have to find out derivative

Q: Resuelva yDx - 2(x+y) Dy=0 O x² + 2y = cy² Ox+2=cy² O x + 2y = cy² Ox+2y=c

A: Given differential equation y D x-2(x+y) D y=0 The objective is to solve the differential equation.

Q: 3 If z= then: (2x² + y² )² ' dz az + y- -4z he dz dz + y- 4% az dz + x- y- = 4z az az = -4z

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Q: !Solve the boundary-value problem y" +9y = 0, y(0) = -3 and y(/3) = 2.

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Q: If y+3y = 8 then g- solution is %3D a- y + 6 = 1 b- In (8 -3y ) = x + c %3D

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Q: Differentiate x + y = e2x+2y A. 1 – 2e2x+2y 1+ 2e2x+2y y' В. -1 + 2e²x+2y 1 – 2e2x+2y y' | С. ||

A: Given query is to find the derivative of the expression.

Q: 1. (3r'y+4.xy' +6}tx + (* + ór*y -1lky = 0

A: Given differential equation is (3x²y + 4xy³ + 6)dx + (x³ + 6x²y² - 1)dy = 0

Q: If ||X|| = 3, ||Y|| =1 and X Y = -2, then (X - 2Y) (3X + 5Y) is equal to

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Q: Solve S(y + 1) + S(2y -5) = 3

A: Given equation: y+1+2y-5=3 Concept: Here we shall first remove the root by squaring both sides.…

Q: 1. уд y = 5x -x y=Vx+2 (4, 4) X= 2 y x x+1 y = 1 2.

A: "Since you have posted multiple figures, we will answer the  questions 1,2 and 3.  If you want…

Q: 4. Solve S/² x + ²/2 y = − 3 y=x+2 using elimination method

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Q: Solve for x,y,z:  3x +2y − z = − 1  − 2x − 2y +3z = 5 5x +2y − z = 3

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Q: 3. What is the particular solution if y(1) = 0 • xy' = y+ (x² + y²) ||

A: Given:- xy' = y+(x2+y2)1/2 y(1) = 0  To find:- Particular solution of given differential equation

Q: What value of c will satisfy y(x) = c(1 – x²) given y(2) = 1 ? %3D ) Option 1 Option 2 2.

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Q: Q9 Solution of + (x + 2) y² = 0 using separation variable is 1 1 y +2x+c y = 2x- 2 22 +c 1 +2x+c…

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Q: 2y + z = 1 29. у + 2z 3D 5 y (x + y + 3z = 8

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Q: 10. Particular solution of y" - 5y' = x-2, when x = 0, y = 0, y = 2

A: To find the particular solution of given differential equation :-

Q: Particular solution of y' = x+xy²/4y, y(1) = 0

A: Given differential equation- y'=x+xy24y   , y(1)=0 We need to find particular solution of the given…

Q: 4. dr/dt = –2tr, 5. y' = -4x/y, y(2) = 3 r(0) = ro

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Q: VAy 5-y-z 15z dz dz dy 2y2 2-y-

A: SOLUTION-

Q: = 2 + Vy - 2x + 3 (reduction to separation of variables) 1. dr dy

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Q: 7) Given: mZ1=x+2y; mZ2=46 °;mZ3=10x+2y Find: x and y 2 3

A: ∠1+∠2= 180 - 90 = 90 degree  So, x+2y+46=90  x+2y=44 x=44-2y

Q: 4y² –7y–12 – , dy + y3-y2-6y dy + dy + dy 5(у-3) 9 5(у+2)

A: Given: ∫124y2-7y-12y3-y2-6ydy=∫1295y+2+2ydy+15y-3dy To find the solution. Solution: We have given,…

Q: dy 3y y torh(x) + 2

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Q: The particular solution to y" + 2y' + y = x is: 8 Select one: 15 a. 1 X. 22 29 b. 2x- 1 Finish Time…

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Q: Vy² – 25 dy y3

A: SINCE YOU HAVE ASKED MULTIPLE QUESTIONS IN SINGLE REQUEST, WE WILL BE ANSWERING ONLY THE FIRST…

Q: 5 +4y = 2 y(0)=1 dt

A: Given problem is:

Q: yz 4. II »z dr dy dz Jo

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Q: max x+ y2 + z² subject to x2 + y² + 4z² == 1 and x+3y + 2z = 0

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Q: X-3y+z--1 3x-y+2z-2 2x + 3y -z= 1 Eat Ax B A-B 3.

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Q: Evaulate: 2 1 pr+y (x)dzdydx 0.

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Q: 10 1 y = 5 dt y(0) = -1 = 2 ot

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Q: How can I solve these two subtituions problem?  1- y= 3x-3 4x-2y=-2 2) 4x+3y--1    6x-5y=27

A: (1) Consider the given first equation.