1)Calculate the acceleration of the skier on AB and the distance AB. 2)Applying Newton's second law, calculate the force of friction acting on the skier during its downward motion on AB.

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Chapter1: Units, Trigonometry. And Vectors
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During a ski competition, a skier moves on a track ABOC situated in a vertical plane as shown in the adjacent figure. The skier, starts from A from rest, he descends on AB in a uniformly accelerated rectilinear motion, and reaches B with a speed of 22 m/s. The duration of motion of the skier between A and B is 9.67 s. Given: AB is inclined by an angle a = 22° with respect to the horizontal. The mass of the skier: m = 80 kg. g = 9.8 m/s. 1)Calculate the acceleration of the skier on AB and the distance AB. 2)Applying Newton's second law, calculate the force of friction acting on the skier during its downward motion on AB. 3)At the point 0, the skier becomes air born, at t = 0, with a speed Ve = 21 m/s making an angle B = 50° with the horizontal. Neglect air resistance. a)Determine, in the system (xOy) of the figure, the parametric equations of motion of the center of inertia of the skier. Deduce the equation of his trajectory. b)Determine the coordinates of the point of impact I of the skier on the part OC on the track which forms with the horizontal an angle 8 = 35°.
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