Solution Given that, and F.T X(t) = y(t) = x (2+-1) ēst x(w) and x(w) 1. F{y(t)} = Y(w) = (y(t) = just Šortes esiet of dt S ēj (w+1 2 √x (2²-1) 2³² ē -jt-just x(z)e dt 5x (2+-1) ēj (w+1st of dt -j(w+1) Z+1 dž (X (Z) e J (+1) Z dz BO = Ł Let 2t-1 ⇒d(2+-1) =dz +2dt = dz Z = (2+ju)² How did he get the value inside the circle os Z+1
Solution Given that, and F.T X(t) = y(t) = x (2+-1) ēst x(w) and x(w) 1. F{y(t)} = Y(w) = (y(t) = just Šortes esiet of dt S ēj (w+1 2 √x (2²-1) 2³² ē -jt-just x(z)e dt 5x (2+-1) ēj (w+1st of dt -j(w+1) Z+1 dž (X (Z) e J (+1) Z dz BO = Ł Let 2t-1 ⇒d(2+-1) =dz +2dt = dz Z = (2+ju)² How did he get the value inside the circle os Z+1
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter9: Systems Of Equations And Inequalities
Section9.10: Partial Fractions
Problem 15E
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Transcribed Image Text:Solution
and
Given that,
F.T
x (t) =
i. F{y(t)}
X (w) and X (w)
y(t) = x (2+−1) ēst
yes evot
= Y(u) = Sylt) @jost
df
-jt-just
df
(²x (2+-1) @j (w+1) t
= Sx(2+-1) e. ē
=jace)
=j (w +¹ ) [x (Z) e
2
-j(w+1) = +¹
dz
-j (w+1) Z
dz
t
=
Z
df
Let 2t-1 = Z
=d(2²-1) =dz
→2d4
= dz
=
W
(2+jwj2
How did he get the value
inside the circle
os
Z+1
2
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