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Sir please Solve both mcq's
![4)public class Test2 {
public static void main(String[] args) {
StringBuffer s1 = new StringBuffer("Complete");
s1.setCharAt(1,'i');
s1.setCharAt(7,'d'
);
System.out.printın
(s1);
}
}
a)Complete
b)lomplede
c)Cimpletd
d)Coipletd](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Feae7ab1e-2201-4dbc-ac63-6f75481d72d9%2Fd0441791-15b4-47da-b2e2-866e01ba99b0%2Ffihx6do_processed.jpeg&w=3840&q=75)
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- public static String pancakeScramble(String text) This nifty little problem is taken from the excellent Wolfram Challenges problem site where you can also see examples of what the result should be for various arguments. Given a text string, construct a new string by reversing its first two characters, then reversing the first three characters of that, and so on, until the last round where you reverse your entire current string.This problem is an exercise in Java string manipulation. For some mysterious reason, the Java String type does not come with a reverse method. The canonical way to reverse a Java string str is to first convert it to mutable StringBuilder, reverse its contents, and convert the result back to an immutable string, that is,str = new StringBuilder(str).reverse().toString(); Here's the tester it must pass: @Test public void testPancakeScramble() throws IOException {// Explicit test casesassertEquals("", P2J3.pancakeScramble(""));assertEquals("alu",…public static String pancakeScramble(String text) This nifty little problem is taken from the excellent Wolfram Challenges problem site where you can also see examples of what the result should be for various arguments. Given a text string, construct a new string by reversing its first two characters, then reversing the first three characters of that, and so on, until the last round where you reverse your entire current stringPublic class Utilities { getDigits Method: public static java.lang.String getDigits(java.lang.String str) Returns a string with the digits (if any) present in the str parameter. You can assume str will never be null. You can use Character.isDigit() to determine whether a character is a digit. You may not use an auxiliary method in order to implement this method. Your implementation must be recursive and you may not use any loop construct. From the String class, the only methods you can use are length(), isEmpty(), charAt() and substring. Do not use ++ or -- in any recursive call argument. It may lead to an infinite recursion. For example, use index + 1, instead of index++. Parameters: str - Returns: String with digits or empty string
- Java Without using any java functions, data structures, libraries, string builder or anything complicated. Please make a program that takes out the tokens in a string. For example "90+5" -> 90 + 5 Make It so it is null if string is empty " " --> null Make it so it is null if expression is invalid "++7 - 0" --> null and "..7 + 0" --> null Use this for loop to iterate through the list for (int i = 0; i < exprn.length(); i++) {private static String extractVowelHelper(String str, int start, String vowels) { // base case // recursive step }Fix all the errors in the code // Program displays some facts about a string public classDebugSeven3 { public static void main(String[] args) { String quote = "Honesty is the first chapter in the book of wisdom. - Thomas Jefferson"; System.out.println("index.of('f') is: " + quoteindexOf('f')); System.out.println("index.of('x') is: " + quoteindexOf('x')); System.out.println("char.At(5) is: " + quote.charAt(50)); System.out.println("endsWith(\"daughter\") is: " + quote.endsWith("daughter")); System.out.println("endsWith(\"son\") is: " + quote.endsWith("son")); System.out.println("replace('e', '*') is: ", quote.replace('e', '*')); } }
- Use for loop in Java language Write the method stringSplosion().* * The method takes one parameter, a non-empty String str (such as "Code") and* returns a String in the form "CCoCodCode". Notice that this includes the* first character of the original String, followed by the first two characters,* and so on until the whole String is used.* * Examples: stringSplosion("Code") returns "CCoCodCode" stringSplosion("abc")* returns "aababc" stringSplosion("x") returns "x"* * @param str the input String to process.* @return a new String as described above.java: Run length coding is a method to represent a string in a more compact manner. Each character that occurs more than 2 times in a row is represented by the character and a number following it. Two examples are: "abba" → "abba""abcccbbbba" → "abc3b4a"Write a function that calculates how many characters the encoded string is shorter than the original.Make the code output sentence starts with a capitalization, and ends with a period. public class Word implements IWord{ private String word; public Word(String word){ this.word = word; } @Override public String getWord(){ return word; }} public class CompoundWord implements IWord { private IWord word1; private IWord word2; public CompoundWord(IWord w1, IWord w2){ word1 = w1; word2 = w2; } @Override public String getWord(){ return word1.getWord() + word2.getWord(); } } import java.util.ArrayList;public class Sentence { private ArrayList<IWord> words; public Sentence(){ words = new ArrayList<IWord>(); } public Sentence add(IWord word){ words.add(word); return this; } public String getSentence(){ String result = ""; for(IWord word:words) result += word.getWord()+" "; return…
- JAVA Language: Transpose Rotate. Question: Modify Transpose.encode() so that it uses a rotation instead of a reversal. That is, a word like “hello” should be encoded as “ohell” with a rotation of one character. (Hint: use a loop to append the letters into a new string) import java.util.*; public class TestTranspose { public static void main(String[] args) { String plain = "this is the secret message"; // Here's the message Transpose transpose = new Transpose(); String secret = transpose.encrypt(plain); System.out.println("\n ********* Transpose Cipher Encryption *********"); System.out.println("PlainText: " + plain); // Display the results System.out.println("Encrypted: " + secret); System.out.println("Decrypted: " + transpose.decrypt(secret));// Decrypt } } abstract class Cipher { public String encrypt(String s) { StringBuffer result = new…Complete the isPalindrome method to recursively determine whether the parameter str is a palindrome. import java.util.*; public class PalindromeDetector{ public static boolean isPalindrome(String str){ /*********************************** WRITE THIS METHOD **********************************/ return false; //temporary statement to allow compilation } public static void main(String[] args){ List<String> allWords = new ArrayList<String>(); Scanner input = new Scanner(System.in); System.out.println("Enter a string, 0 to quit"); String str = input.nextLine(); while (!str.equals("0")){ allWords.add(str); System.out.println("Enter a string, 0 to quit"); str = input.nextLine(); } List<String> palindromes = new ArrayList<String>(); for (String test : allWords) { if (isPalindrome(test.toUpperCase())){ palindromes.add(test); } } Collections.sort(palindromes); if (!palindromes.isEmpty()){ System.out.println("Your palindromes are:");…Subject - Data Structure Please help me to debug my error. Thank you in advance! import java.util.Scanner;public class LinearSearchDemo { private static int linearSearch(int[] numbers, int key) { for (int i = 0; i < numbers.length; i++) { if (numbers[i] == key) { return i; } } return -1; // not found } // Main program to test the linearSearch() method public static void main(String[] args) { int[] numbers = { 2, 4, 7, 10, 11, 32, 45, 87 }; System.out.print("NUMBERS: "); for (int i = 0; i < numbers.length; i++) { System.out.print(numbers[i] + " "); } System.out.println(); Scanner scnr = new Scanner(System.in); System.out.print("Enter an integer value: "); int key = scnr.nextInt(); int keyIndex = linearSearch(numbers, key); if (keyIndex == -1) { System.out.println(key + " was not found."); } else { System.out.printf("Found %d at index…
