T/F 5) The following two methods will both compute the same thing when invoked with the same value of x. That is, method1(x) = = method2(x). public int method1(int x) { if(x > 0) return method1(x – 1) + 1; else return 0; } public int method2(int x) { if(x > 0) return 1 + method2(x – 1); else return 0; }

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