Question
Asked Sep 9, 2019
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(1/y)+(6/y^2−100)−(3/y^2−10y)

 

how do i find the LCD then solve?

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Expert Answer

Step 1

First we factor y^2-100= y^2-10^2= (y+10)(y-10) [used a^2 - b^2=(a+b)(a-b) formula]

 

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y2- 100 —у-10° (y+10)(y-10) =

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Step 2

Then we factor y^2-10y using GCF method. 

y^2-10y=y(y-10)

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у'-10y 3У (у-10)

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Step 3

LCD= y(y+10)(y-10)

We make ever...

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6 3 1 -+ у'-100 у?-10у у 6 1 -+ 3 (у+10)(у-10) У(у-10) бу у (у+10)(у-10) 3(у+10) -+ Уу+10)(у-10) У(у+10)(у-10) У(у+10)(у-10)

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