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2 1 7 4 and v = 6 Compute Au and Av, and compare them with b. Is it possible that at least one of u or v could be a Let A = -9 - 3 - 36 u= - 3 4 33 least-squares solution of Ax = b? (Answer this without computing a least-squares solution.) Au = (Simplify your answer.) Av = (Simplify your answer.) Compare Au and Av with b. Is it possible that at least one of u or v could be a least-squares solution of Ax = b? O A. Av is closer to b than Au is. Thus, u cannot be a least-squares solution of Ax = b, but v can be. O B. Au is closer to b than Av is. Thus, v cannot be a least-squares solution of Ax = b, but u can be. C. Au and Av are equally close to b. Thus, both can be the least-squares solution of Ax = b. O D. Au and Av are equally close to b. Thus, neither can be the least-squares solution of Ax = b.

2 1 7 4 and v = 6 Compute Au and Av, and compare them with b. Is it possible that at least one of u or v could be a Let A = -9 - 3 - 36 u= - 3 4 33 least-squares solution of Ax = b? (Answer this without computing a least-squares solution.) Au = (Simplify your answer.) Av = (Simplify your answer.) Compare Au and Av with b. Is it possible that at least one of u or v could be a least-squares solution of Ax = b? O A. Av is closer to b than Au is. Thus, u cannot be a least-squares solution of Ax = b, but v can be. O B. Au is closer to b than Av is. Thus, v cannot be a least-squares solution of Ax = b, but u can be. C. Au and Av are equally close to b. Thus, both can be the least-squares solution of Ax = b. O D. Au and Av are equally close to b. Thus, neither can be the least-squares solution of Ax = b.

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.4: Mathematical Induction
Problem 42E
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2 1 7 4 and v = 6 Compute Au and Av, and compare them with b. Is it possible that at least one of u or v could be a Let A = -9 - 3 - 36 u= - 3 4 33 least-squares solution of Ax = b? (Answer this without computing a least-squares solution.) Au = (Simplify your answer.) Av = (Simplify your answer.) Compare Au and Av with b. Is it possible that at least one of u or v could be a least-squares solution of Ax = b? O A. Av is closer to b than Au is. Thus, u cannot be a least-squares solution of Ax = b, but v can be. O B. Au is closer to b than Av is. Thus, v cannot be a least-squares solution of Ax = b, but u can be. C. Au and Av are equally close to b. Thus, both can be the least-squares solution of Ax = b. O D. Au and Av are equally close to b. Thus, neither can be the least-squares solution of Ax = b.
Transcribed Image Text:2 1 7 4 and v = 6 Compute Au and Av, and compare them with b. Is it possible that at least one of u or v could be a Let A = -9 - 3 - 36 u= - 3 4 33 least-squares solution of Ax = b? (Answer this without computing a least-squares solution.) Au = (Simplify your answer.) Av = (Simplify your answer.) Compare Au and Av with b. Is it possible that at least one of u or v could be a least-squares solution of Ax = b? O A. Av is closer to b than Au is. Thus, u cannot be a least-squares solution of Ax = b, but v can be. O B. Au is closer to b than Av is. Thus, v cannot be a least-squares solution of Ax = b, but u can be. C. Au and Av are equally close to b. Thus, both can be the least-squares solution of Ax = b. O D. Au and Av are equally close to b. Thus, neither can be the least-squares solution of Ax = b.
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