7. 3 1 13 8 Compute Au and Av, and compare them with b. Is it possible that at least one of u or v could be a -8 Let A = -6 -9 b3D 30 u = and v = - 8 6 -6 least-squares solution of Ax b? (Answer this without computing a least-squares solution.) Au = (Simplify your answer.) Av = (Simplify your answer.) Compare Au and Av with b. Is it possible that at least one of u or v could be a least-squares solution of Ax = b? O A. Av is closer to b than Au is. Thus, u cannot be a least-squares solution of Ax = b, but v can be. O B. Au is closer to b than Av is. Thus, v cannot be a least-squares solution of Ax = b, but u can be. OC. Au and Av are equally close to b. Thus, both can be the least-squares solution of Ax = b. O D. Au and Av are equally close to b. Thus, neither can be the least-squares solution of Ax = b.

Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter2: Systems Of Linear Equations
Section2.4: Applications
Problem 2EQ: 2. Suppose that in Example 2.27, 400 units of food A, 500 units of B, and 600 units of C are placed...
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Question
7.
3
1
13
Let A =
-6 -9
b =
30
u =
and v =
Compute Au and Av, and compare them with b. Is it possible that at least one of u or v could be a
- 8
- 8
6
-6
least-squares solution of Ax = b?
(Answer this without computing a least-squares solution.)
Au =
(Simplify your answer.)
Av =
(Simplify your answer.)
Compare Au and Av with b. Is it possible that at least one of u or v could be a least-squares solution of Ax = b?
O A. Av is closer to b than Au is. Thus, u cannot be a least-squares solution of Ax = b, but v can be.
O B. Au is closer to b than Av is. Thus, v cannot be a least-squares solution of Ax = b, but u can be.
O C. Au and Av are equally close to b. Thus, both can be the least-squares solution of Ax = b.
D. Au and Av are equally close to b. Thus, neither can be the least-squares solution of Ax = b.
Transcribed Image Text:7. 3 1 13 Let A = -6 -9 b = 30 u = and v = Compute Au and Av, and compare them with b. Is it possible that at least one of u or v could be a - 8 - 8 6 -6 least-squares solution of Ax = b? (Answer this without computing a least-squares solution.) Au = (Simplify your answer.) Av = (Simplify your answer.) Compare Au and Av with b. Is it possible that at least one of u or v could be a least-squares solution of Ax = b? O A. Av is closer to b than Au is. Thus, u cannot be a least-squares solution of Ax = b, but v can be. O B. Au is closer to b than Av is. Thus, v cannot be a least-squares solution of Ax = b, but u can be. O C. Au and Av are equally close to b. Thus, both can be the least-squares solution of Ax = b. D. Au and Av are equally close to b. Thus, neither can be the least-squares solution of Ax = b.
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