(2+) ( 29 3 7. Suppose that lim In .Fill in the boxes for the corresponding equation involving the definite integral. Upper bound dx = Lower bound The function f(x) The value of the definite integral

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
6th Edition
ISBN:9781337111348
Author:Bruce Crauder, Benny Evans, Alan Noell
Publisher:Bruce Crauder, Benny Evans, Alan Noell
Chapter1: Functions
Section1.2: Functions Given By Tables
Problem 32SBE: Does a Limiting Value Occur? A rocket ship is flying away from Earth at a constant velocity, and it...
icon
Related questions
Question

(Please only solve after reviewing the given formula sheet. Thank you)

(P7)

 

EXTREMA AND CRITICAL POINTS
c is a critical point of fif either f'(c) = 0 or f'(c) does not exist.
f(c) is an absolute maximum value of fiff (c) >f(x) for all x in the domain of f.
f(c) is an absolute minimum value of fif f(c) < f(x) for all x in the domain of f.
f(c) is a relative minimum value of fiff(c) 2 f (x) for all x near c.
f(c) is a relative maximum value of fiff(c) < f(x) for all x near c.
EXTREME VALUE THEOREM
FERMAT’S THEOREM
If fis continuous on a closed and bounded interval [a, b], then f
Iff(c) is a relative maximum or minimum value, then f'(c) = 0
attains a maximum and minimum on the interval.
ROLLE'S THEOREM
MEAN VALUE THEOREM
Let f be a function which satisfies the following:
Let f be a function which satisfies the following:
1. fis continuous on the closed interval [a, b].
1. fis continuous on the closed interval [a, b].
2. fis differentiable on the open interval (a, b).
2. fis differentiable on the open interval (a, b).
3. f(a) = f (b).
Then there is some c in the interval (a, b) where
Then there is some c in the interval (a, b) where f'(c) = 0.
f(a) – f(b)
f'(c) =
а —Ь
CALCULUS AND GRAPHS
If f'(x) > 0 on some interval (a,b), then f is increasing on (a, b).
If f'(x) < 0 on some interval (a,b), then f is decreasing on (a, b).
First Derivative Test:
Suppose c is a critical point of some function f.
a. Iff' changes from positive to negative at c, then f(c) is a relative maximum.
b. Iff' changes from negative to positive at c, then f(c) is a relative minimum.
c. If the sign of f' does not change while passing c, then f(c) is neither a maximum nor a minimum (it is a saddle point).
If f"(x) > 0 on some interval (a,b), then fis concave up on (a, b).
If f"(x) <0 on some interval (a, b), then f is concave down on (a, b).
Second Derivative Test:
Suppose c is a critical point of some function f.
a. If f"(c) < 0, then f(c) is a relative maximum.
b. If f"(c) > 0, then f(c) is a relative minimum.
c. If f"(c) = 0, then the test is inconclusive. (Could be a maximum, minimum, or saddle).
L’HOPTIAL’S RULE
AREA APPROXIMATION
ƒ(x)
takes either the
The area under a curve can be approximated using rectangles with
either right or left endpoints. You can subdivide an interval [a, b]
Iff and g are differentiable near a and lim =
x-a g(x)
00
or
then
b - a
for n rectangles by taking segments of length -
indeterminate form
00
f(x)
lim
f'(x)
= lim
x-a g'(x)
f(x)dx = lim
f(x*)Ax.
X-a g(x)
n00
i=1
Transcribed Image Text:EXTREMA AND CRITICAL POINTS c is a critical point of fif either f'(c) = 0 or f'(c) does not exist. f(c) is an absolute maximum value of fiff (c) >f(x) for all x in the domain of f. f(c) is an absolute minimum value of fif f(c) < f(x) for all x in the domain of f. f(c) is a relative minimum value of fiff(c) 2 f (x) for all x near c. f(c) is a relative maximum value of fiff(c) < f(x) for all x near c. EXTREME VALUE THEOREM FERMAT’S THEOREM If fis continuous on a closed and bounded interval [a, b], then f Iff(c) is a relative maximum or minimum value, then f'(c) = 0 attains a maximum and minimum on the interval. ROLLE'S THEOREM MEAN VALUE THEOREM Let f be a function which satisfies the following: Let f be a function which satisfies the following: 1. fis continuous on the closed interval [a, b]. 1. fis continuous on the closed interval [a, b]. 2. fis differentiable on the open interval (a, b). 2. fis differentiable on the open interval (a, b). 3. f(a) = f (b). Then there is some c in the interval (a, b) where Then there is some c in the interval (a, b) where f'(c) = 0. f(a) – f(b) f'(c) = а —Ь CALCULUS AND GRAPHS If f'(x) > 0 on some interval (a,b), then f is increasing on (a, b). If f'(x) < 0 on some interval (a,b), then f is decreasing on (a, b). First Derivative Test: Suppose c is a critical point of some function f. a. Iff' changes from positive to negative at c, then f(c) is a relative maximum. b. Iff' changes from negative to positive at c, then f(c) is a relative minimum. c. If the sign of f' does not change while passing c, then f(c) is neither a maximum nor a minimum (it is a saddle point). If f"(x) > 0 on some interval (a,b), then fis concave up on (a, b). If f"(x) <0 on some interval (a, b), then f is concave down on (a, b). Second Derivative Test: Suppose c is a critical point of some function f. a. If f"(c) < 0, then f(c) is a relative maximum. b. If f"(c) > 0, then f(c) is a relative minimum. c. If f"(c) = 0, then the test is inconclusive. (Could be a maximum, minimum, or saddle). L’HOPTIAL’S RULE AREA APPROXIMATION ƒ(x) takes either the The area under a curve can be approximated using rectangles with either right or left endpoints. You can subdivide an interval [a, b] Iff and g are differentiable near a and lim = x-a g(x) 00 or then b - a for n rectangles by taking segments of length - indeterminate form 00 f(x) lim f'(x) = lim x-a g'(x) f(x)dx = lim f(x*)Ax. X-a g(x) n00 i=1
(2+=)
3
=- In
29
Fill in the boxes for the corresponding equation
7. Suppose that lim )
+4
involving the definite integral.
Upper bound
Jdx =
%3D
Lower bound
The function f (x)
The value of the
definite integral
Transcribed Image Text:(2+=) 3 =- In 29 Fill in the boxes for the corresponding equation 7. Suppose that lim ) +4 involving the definite integral. Upper bound Jdx = %3D Lower bound The function f (x) The value of the definite integral
Expert Solution
steps

Step by step

Solved in 2 steps

Blurred answer