2 Al + 2KOH + 6H2O = 2KAl(OH)4 + 3H2 Assuming more than enough water, 3.0 moles of aluminum, and 4.0 moles of potassium hydroxide, how many moles of KAl(OH)4 can you make
2 Al + 2KOH + 6H2O = 2KAl(OH)4 + 3H2 Assuming more than enough water, 3.0 moles of aluminum, and 4.0 moles of potassium hydroxide, how many moles of KAl(OH)4 can you make
Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter4: Stoichiometry: Quantitative Information About Chemical Reactions
Section4.1: Mass Relationships In Chemical Reactions: Stoichiometry
Problem 1RC: Aluminum reacts with Cl2 to form AlCl3. If you have 0.40 mol of Al, what amount (moles) of Cl2 is...
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2 Al + 2KOH + 6H2O = 2KAl(OH)4 + 3H2
Assuming more than enough water, 3.0 moles of aluminum, and 4.0 moles of potassium hydroxide, how many moles of KAl(OH)4 can you make
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