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-2 Au = -5 and Au = 2 then A(-2ü – 35) =

-2 Au = -5 and Au = 2 then A(-2ü – 35) =

Linear Algebra: A Modern Introduction
Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter4: Eigenvalues And Eigenvectors
Section4.2: Determinants
Problem 11AEXP
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-2 Au -5 and A = %3D -3 then A(-2ủ – 30) =
Transcribed Image Text:-2 Au -5 and A = %3D -3 then A(-2ủ – 30) =
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