2- Calculate the values of Ro, X,, Reg1 and Xeg1 of the equivalent circuit of a 1-ph, 4KVA, 200/400V, 50HZ transformer of which the following are test results: open-circuit: 200V, 0.7A and 70W on low-voltage (primary) side. Short-circuit: 15V, 10A and 80W on high-voltage (secondary) side.
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- A two-winding single-phase transformer rated 60kVA,240/1200V,60Hz, has an efficiency of 0.96 when operated at rated load, 0.8 power factor lagging. This transformer is to be utilized as a 1440/1200-V step-down autotransformer in a power distribution system. (a) Find the permissible kVA rating of the autotransformer if the winding currents and voltages are not to exceed the ratings as a two-winding transformer. Assume an ideal transformer. (b) Determine the efficiency of the autotransformer with the kVA loading of part (a) and 0.8 power factor leading.The transformer of Problem 3.16 is supplying a rated load of 50 kVA at a rated secondary voltage of 240 V and at 0.8 posr factor lagging. Neglect the transformer exciting current. (a) Determine the input terminal voltage of the transformer on the high-voltage side. (b) Sketch the corresponding phasor diagram. (c) If the transformer is used as a step-down transformer at the load end of a feeder whose impedance is 0.5+j2.0, find the voltage VS and the power factor at the sending end of the feeder.Consider a source of voltage v(t)=102sin(2t)V, with an internal resistance of 1800. A transformer that can be considered as ideal is used to couple a 50 resistive load to the source. (a) Determine the transformer primary-to-secondary turns ratio required to ensure maxi mum power transfer by matching the load and source resistances. (b) Find the average power delivered to the load, assenting maximum power transfer.
- A Transformer with 10:1 ratio and rated at 50-kVA, 2400/240-V, 50-Hz is used to step down the voltage of a distribution system. The low-tension voltage is to be kept constant, if the transformer has: R = 2.2 0, R2 = 0.014 Q, X, = 4.1 0, X2 = 0.03 0, then, a. What load impedance connected to low-tension side will be loading the transformer fully. b. Calculate the equivalent resistance as referred to primary. c. Calculate the equivalent reactance as referred to primary. d. Calculate the equivalent impedance as referred to primary. e. Calculate the total Cu loss.A transformer with a 10:1 ratio and rated at 60kVA, 2200/220V, 60Hz is used to step down the voltage of a distribution system. The low tension voltage is to kept constant at 220V. (a) What load Impedance connected to the low-tension side will be loading the transformer fully at 0.8 power factor (lag) ? (b) What is the value of this impedance referred to the high tension side?In a 100-kVA, 6,000/400-V, Y-Y, 3-ph, 50-Hz transformer, the copper loss is measured at 5000 W during half-load. Apparently, the maximum efficiency also occurs at ¾ full-load, find the efficiencies of the transformer at full-load and at half-load both at 0.8 pf
- A 2.4-kVA, 2400/240-V, 50-Hz, step-down transformer has the followingparameters: R, = 1.5 a, X, = 2.5 R, R, = 0.02 a, X, = 0.03 Q, R,, = 6 kR,and X,, = 8 kR. It is operating at 80% of its load at unity power factor.Using the exact equivalent circuit embodying the ideal transformer, determine the efficiency of the transformer. Also sketch its phasor diagram.A 2,300/240-V, 60-Hz, 4.6-kVA transformer isdesigned to have an induced emf of 2.5 V/turn.Assuming an ideal transformer, finda. The numbers of high-side turns Nh and low-sideturns Nl .b. The rated current of the high-voltage side Ih.c. The transformer ratio when the device is used as astep-up transformer.Primary side-reduced equivalent circuit parameters of a 25 KVA, 50 Hz, 4000/400 Volt transformer R1 = 32 Ω, X1 = 45 Ω, Rc = 250000 Ω, R2 '= 66.14 Ω, X2' = 79.34 Ω, Xm It is given as = 30000 Ω. Since the secondary of the transformer is fed at a full load rated voltage with an advanced power factor of 0.9, for these operating conditions; a) Calculate the primary voltage using the T equivalent circuit. (Only the amplitude of the voltage and the phase value will not be entered.) b) Calculate the efficiency of the transformer. c )Calculate the voltage regulation of the transformer.
- A 25-kVA, 4000/400-V, 60-Hz transformer has the following parameters:R, = 18 Q, X, = 25 0, R, = 180 mQ, X, = 250 mQ, R,, = 15 kQ, andX,, = 25 kQ. If the open-circuit and short-circuit tests are performed onthis transformer, what are the readings of the instruments in each case? From the data given in above, determine the rating of the transformerat maximum efficiency. What is the maximum efficiency of thetransformer at unity power factor? What is the efficiency at full load andunity power factor?1.The equivalent parameters of a 150kVA, 2400V/240V transformer, are R1=0.2Ω, R2=2mΩ, X1=0.45Ω, X2=4.5mΩ, Rc=10kΩ, and Xm=1.55kΩ. The transformer is operating at rated load and rated voltage with 0.8 lagging power factor. Using the approximate equivalent circuit referred to the primary side, determine: (i) (i) the voltage regulation (ii) (ii) the transformer power loss and efficiency 2.Nanoscale drives occur in the living world for example in the bacterial flagellum or ATP synthase. For one of these drives describe with the aid of diagrams how it operates and discuss the features which the drive has in common with large scale, man-made counterparts. 3.A 15 kW, 250V shunt motor with Ra=0.22 Ω, Rf=170 Ω. At no-load and rated voltage, the speed is 1200 rpm and the armature current is 3 A. At full-load and rated voltage, the line current is 55A. What is the full-load speed?630kVA 31500/400 DY 50Hz transformer has no load and short circuit tests power measurements are given as 1kW and 20kW respectively. Under the fourth of the nominal load with 0,85 capacitive power factor, calculate the efficiency of the transformer at nominal voltage as %?