2) Find the resultant of the three forces in the figure below (add them together). 2 m 2m F- 350 N 3 m Fc- 400 N F-400 N 2 m 3 m
2) Find the resultant of the three forces in the figure below (add them together). 2 m 2m F- 350 N 3 m Fc- 400 N F-400 N 2 m 3 m
International Edition---engineering Mechanics: Statics, 4th Edition
4th Edition
ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
Publisher:Andrew Pytel And Jaan Kiusalaas
Chapter6: Beams And Cables
Section: Chapter Questions
Problem 6.18P: For the ladder in Prob. 6.17, find the internal force system acting on section 2, assuming that x <...
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Transcribed Image Text:2)
Find the resultant of the three forces in the figure below (add them together).
2 m
2m
E
B
Fg = 350 N
3 m
Fc= 400 N,
F#= 400 N
2 m
3 m
![- 50 + 23 +3W
6.16
ans 2:- the resulatnt of the three torces is the net ettect of the three torces combine together to give the
AB
TAB
Simılozly
AB
single component. to get the resultant of the three forces first calculate unit vectors.
Sol
A 51 + oj +0k
* 07 +21 +3 k
fonce Comboenent along IPB) Y00N
IPAB) - 824.47 +189. 6 J t194.84 ĥ -O
Ac C Gu - Au) î + CCy -Ag)Î + (Cz -A2) R)
- 51 + - 23 + 3-R
Unit vecar Courespon to
AC
Simlanly Calculale
AC Vecor
mogniludu af AC
20 + 3 R
Js?+ 22 +8?
AC
AC
-21 + 07 +3R
51-27 +3k
6.16
- -ST -
DE =
Ju+ 9
-0.811 T - 0.824be Ĵ t .487k
+
3.Go
Goe know foxce olong Ac a
400 N
-0.55 1 +0 t0.883 k
TFel 8S0 N
Pe a -324.41 129.6J + 9y.8 Ř { y00X AC} O
fe 9So x (BE)
9350 x [ -0.s5 î +0] +0.833 h )
19259 + 01 +291 S SR
• 349.36 N - 9
- 3)
Resultant al Pe and Fe ae
FR
add eq O ond ®
* - 648 8T +oĵ + 398. 68
* 7 GI.SO N
A 90 -56.36
33.7
S9.04 -33.7
A 25.34
FR
9o -30.96
)59.04
3
A FE
30.96
56-300
2 fooce
fe a JIFR)? + If?+ 2 FRife) Cas O
J761502 + 849.36 + 2×76) Sd x34936 ×(as 25.34
JHasultant
1087.57N](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa658c71c-1a2c-47f6-b23a-f861466702f5%2F6bc08894-31cb-4257-85aa-f835535fc86b%2Fpzf6rmo_processed.png&w=3840&q=75)
Transcribed Image Text:- 50 + 23 +3W
6.16
ans 2:- the resulatnt of the three torces is the net ettect of the three torces combine together to give the
AB
TAB
Simılozly
AB
single component. to get the resultant of the three forces first calculate unit vectors.
Sol
A 51 + oj +0k
* 07 +21 +3 k
fonce Comboenent along IPB) Y00N
IPAB) - 824.47 +189. 6 J t194.84 ĥ -O
Ac C Gu - Au) î + CCy -Ag)Î + (Cz -A2) R)
- 51 + - 23 + 3-R
Unit vecar Courespon to
AC
Simlanly Calculale
AC Vecor
mogniludu af AC
20 + 3 R
Js?+ 22 +8?
AC
AC
-21 + 07 +3R
51-27 +3k
6.16
- -ST -
DE =
Ju+ 9
-0.811 T - 0.824be Ĵ t .487k
+
3.Go
Goe know foxce olong Ac a
400 N
-0.55 1 +0 t0.883 k
TFel 8S0 N
Pe a -324.41 129.6J + 9y.8 Ř { y00X AC} O
fe 9So x (BE)
9350 x [ -0.s5 î +0] +0.833 h )
19259 + 01 +291 S SR
• 349.36 N - 9
- 3)
Resultant al Pe and Fe ae
FR
add eq O ond ®
* - 648 8T +oĵ + 398. 68
* 7 GI.SO N
A 90 -56.36
33.7
S9.04 -33.7
A 25.34
FR
9o -30.96
)59.04
3
A FE
30.96
56-300
2 fooce
fe a JIFR)? + If?+ 2 FRife) Cas O
J761502 + 849.36 + 2×76) Sd x34936 ×(as 25.34
JHasultant
1087.57N
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