Are these two problems done correctly? F'x) = -4xt18X8. Write the equation of the line tangent to f(x) = 2x3 – 3x2 + 1at x = -1.%3Dy:fu) =26)°-3し-0+1f(1) = -2-23+13.m: f'(x) = 6x²-6xf'C)= 6と)2-66)f'li) = 6+6%3Dfu)= -5+1f)= -4((-1,-)FICI)=12一→M=12y+4=12(x+1)ニ9. Write the equation of the line tangent line whose slope is -11 for f(x) = (2x – 1)(x – 1).(2x-1)(x-1)2×dx-メ+1||0-11=4x-3fry%3(ac-a)-1)C-2-1)y=(-5)(-3)y = 15+3+3fu) = 2x²-3x+1-8=4xf'X)=4メ-3-2=xy-15 = -11C×ャ2)%3D

Answered: Image /qna-images/answer/5a5bf1c9-2045-4f5b-af26-016385acb6d9.jpg

-2 F'x) = -4x+ 18x 8. Write the equation of the line tangent to f(x) = 2x3 -3x2 + 1at x = -1. y:fu) = 261)3(-1)1 Fい) = -2-3+ fu)= - 5+1 f)= -4((-リり m: f'(x) = 6x?-6x f'C): 6と)?-66) f'l1) = 6+6 %3D fIcI) = 12 y+4=12(xt → Im 12 9. Write the equation of the line tangent line whose slope is -11 for f (x) = (2x – 1)(x – 1). (2×ー)Lx -1) 2x x-x+1 fu)= 2x²-3x+1 y3 (ac-a)-1)(-2-1) t. y = (-5)(-3) +3 +3 -8=4x. f'x)= 4x -3 -2=x y-15 = -|1(x+2) %3D

-2 F'x) = -4x+ 18x 8. Write the equation of the line tangent to f(x) = 2x3 -3x2 + 1at x = -1. y:fu) = 261)3(-1)1 Fい) = -2-3+ fu)= - 5+1 f)= -4((-リり m: f'(x) = 6x?-6x f'C): 6と)?-66) f'l1) = 6+6 %3D fIcI) = 12 y+4=12(xt → Im 12 9. Write the equation of the line tangent line whose slope is -11 for f (x) = (2x – 1)(x – 1). (2×ー)Lx -1) 2x x-x+1 fu)= 2x²-3x+1 y3 (ac-a)-1)(-2-1) t. y = (-5)(-3) +3 +3 -8=4x. f'x)= 4x -3 -2=x y-15 = -|1(x+2) %3D

Calculus: Early Transcendentals

8th Edition

ISBN:9781285741550

Author:James Stewart

Publisher:James Stewart

Chapter1: Functions And Models

Section: Chapter Questions

Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...

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