2/ Let the Polf fext = then E(X) is 2. 225 (30-x) 225 ③2x815 15 ≤x≤ 30

A First Course in Probability (10th Edition)
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Chapter1: Combinatorial Analysis
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Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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2/ Let the Polf
fexs =
then E(x) is 2.
225
(30-x)
225
06x515
15≤x≤ 30
Transcribed Image Text:2/ Let the Polf fexs = then E(x) is 2. 225 (30-x) 225 06x515 15≤x≤ 30
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