(2) lim 12 X+6 (3) lim (2x³ – 3x² +x) x3 - 2x2 +3x-5 (4) lim X2 3-x

Q: x²-2x-3 lim a. (x-3)3 2-2r-3 x-3 (x-3)' x² - 2x-3 b. lim x² - 2x-3 lim 33 (x-3)3 c.

A: x→3+ limx2-2x-3(x-3)3=x→3+lim(x-3)(x+1)(x-3)3=x→3+limx+1(x-3)2=∞

Q: Lim x2-x- X7-2 2-2

A: limx→-2x2-x-4x2-2

Q: x2 - 4x- 21 lim X-7 X-7 x² - 4x-21 lim (Type an integer or a simplified frac- %3D x- 7 X-7

A:

Q: 2x- 14 | lim 7- x |2x – 14| lim %3D 7 - x x7+

A:

Q: Lim    4 - x2      x →2   x + 3 (b). Lim   4 - x2      x →2   x - 2 (c). Lim   1 + 8x + 6x3      x…

A:

Q: L’Hôpital’s Rule is used incorrectly. Describe the error. SNIPP

A:

Q: lim x-2 x²+2x-8 x-2

A:

Q: lim d. x → 2 Vx²-4x+4 lim 4-V21-x C. x → 5 х-2 x-5

A: Given that: c. limx→54-21-xx-5d. limx→2x2-4x+4x-2

Q: 2х x-1 lim X-3 6- 2х

A: Solving the problem by finding the value of the limit.   NOTE :: As per our Expert guidelines we are…

Q: 2-2 + 2" lim 2-x | تقدير القيمة -1

A:

Q: х —2 Га) lim x4-X-4 x- 3 (b) lim х+2 (х — 2)2

A:

Q: 5x-3 – 4 (i) Lim- x-00 2x-2 + 9 (х - 3)2 (ii) Lim X-00 X4 2 7 2x – 3

A:

Q: lim 1 4 X + 2* x-2 In(2x-3)

A:

Q: lim (25-x2 X-D4 lim ( 3x -2) X-D3 lim (ax2 +4x+5) X-DO X+1

A:

Q: (а) 5x-3 – 4 (i) Lim- x-00 2x-2 + 9 | (х — 3)2 (ii) Lim X00 x2 T- 2x – 3

A: Note: According to Bartleby guidelines; For more than one question asked; only the first one is to…

Q: Lim x->4 (x2-3x-4)/ (x-4)

A:

Q: x² + x – 6 - f. lim "3 x² – 9 /x + 1 – 2 g. lim х — 3 * 3 x - 8 h. lim * 2 2 x- 2 3x2 + 5x - 2 i.…

A: Given tha

Q: lim x->3 "x^2 - 3x - 10 / x^2 - 10x + 25"

A:

Q: lim -2 13-x-2

A:

Q: lim | X3-1

A:

Q: x-2 6. lim x-2-2-V4x-x²

A: To find:  limx→2- x-22-4x-x2

Q: lim 8-x3 x→2 (x-2)

A:

Q: 3x2 (x- 1) .2, (а) lim I00 5x(2x2 +1) 2 - x3 (b) lim 1o x2 - 2x + 5 | x - 2 (c) lim x→-0 x4 –2x³ +1

A: As per Bartleby guidelines rule I am answering only first three questions. Evaluate:…

Q: lim 1 2/x2 x→0 3

A: It is in the form of 1^infinity. So i have used the rule for that particular case

Q: lim x-3-j 2 x²-8-j6 2x²− x³ −3l+x −j37

A:

Q: lim x-2x2 +3 x-1 |

A:

Q: lim 2f(x) = 8 x→3- lim f(x) = ∞ x→3+ f(3) = f(4) = 8

A: Given

Q: x-3 lim x-2 x2-4

A: Given that, the function is f(x) = x-3x2-4 To find the limit at x = 2

Q: x - 3 lim I-3 x - 9 x? – 2x – 8 lim x – 4 x³ – 2x? + 1 lim x³ - 1

A:

Q: х2+2х-3 lim X→-1 х2-1

A:

Q: x- 2 5. Evaluate lim- 1→2 Jx+2 - 2 Solution:

A:

Q: a b and c pls

A: To evaluate the following  given limits.

Q: Evaluate

A: alimx→3−1x−3L.H.L x→3− means x approaching 3 from left ,x<3⇒x-3<0⇒limx→3−1x−3=1−0=−∞Or we can…

Q: x2+2x+1 4 - lim (x² +1)2 4x2+2 -2 5 - lim オ→0 2х-2

A:

Q: Зx3-9х2 +х-3 3- lim x-3 x-3

A: On directly substituting the limit we obtain indeterminate form 00, so this is the wrong approach.…

Q: x2+4 lim x-1-x3-1 x+4 lim X-4+ x-4

A:

Q: lim X+0 2-√ 4-X² x ²

A: We can find the answer by finding the limit as below.

Q: X - 4 (a) lim x→4 x´ -x-12 x² - 27 (b) lim .3 x² -9 (x+h)° – x² (c) lim h→0 h ||

A: Limit is the value of the expression as the independent variable approaches certain value, not…

Q: V6-x-2) 1. Find lim 『→2 v3-xー1

A: According to our guidelines we can solve only the first question. Please repost the other questions…

Q: x²-1 Solve for the lim x00 " x2+3x-4

A: To find the given limit

Q: X-3 b. lim X-3+ x2-9

A:

Q: Lim Ix-2 wr メ→2 x4

A:

Q: lim 2x² (x+1) a. b. lim 3(2x+1)* 2'-2r+5x-1 c. lim 2x-3x+1

A: In this question, we find the limit at negative infinity for each of the given functions.

Q: (х— 3)2 Lim 2 X→0 X 7-2х 2 (-3

A: To find limx→∞x-32x22-2x-3.

Q: V4-4x+x' 18. lim x-2 19. lim 4+1-V4-t x-1 20. lim Vx+3-2 7+31 21. lim (t+2)-(1-2)

A:

Q: lim(-3x² – 1) I-3 lim v3x2 - 6 X-2 (x-2)2 lim x-2 x2-4

A: Given that some limit problem and we solve this problem by using general property of limit.     Here…

Q: lim x → ∞0 5x²-x + 1 2x² + 5x - 4

A:

Q: lim(-x² + x-2) x-2 x+5x+4 lim x+2 2 +7x +6 lim I+3

A:

Q: 6 - 8x (a) lim X- 0 6x3 - 2 6 - 8x (b) lim x- 0 6x - 2 6 - 8x2 (c) lim X- 00 бх — 2 II II

A:

Limits

When it comes to calculus, limits are considered to be a very important topic of discussion. The main importance of limit lies in expressing the value of a function as it gets closer to a certain value. Also, limits can help you to understand other topics, such as continuity and differentiability better. In a broader sense, every calculus notion is a limit. Other branches of calculus have also been derived from limits.