2 lnt tyl + 5 lnt dt

Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter5: Factoring Polynomials
Section5.8: Factoring Pattern For X2+bx+c, C Negative
Problem 10MRE
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Question

Integrate using an appropriate formula from the table of integrals. State the formula number, u and du, identify any constants, and show any constant “adjustments” "Multiply by 1” if needed. 

2 lnt
t√1+5lnt
dt
Transcribed Image Text:2 lnt t√1+5lnt dt
16.
17.
18.
19.
20.
21.
22.
[²√a + bu du =
Tu
S
1
u√a+bu
[³
S-
S
1
√√a+bu
a + bu
น
a + bu
Un
-du
-du =
U
√a + bu
du =
-du
un
/a + bu
=
du =
du
=
2
b (2n + 3)
1
Ç
-In
2
-[uº{(a + bu)²"'* _ na fu²+¹ √/a + bu du]
³/2
-
-1
a (n − 1)
√a+bu - √a
√a+bu + √a
:arctan
a (n − 1)
(2n +
2√a+bu+a
af.
-2 (2a - bu)
36²
√a + bu
un-1
a + bu
2
+ 1)6 (2²
-a
+
1
u√a + bu
| (2n − 3)b ſ
2
5 ( u² √a + bu -
+ C, a > 0
−1
17 [(a + dujt², (2n = 536 / Va + bu du] ·
bu) ³/2
- 5)b √a
+
2
UT-1
a + bu + C
+C, a <0
du
1
un-1√a+bu
na
ªf.
un-1
√a + bu
du
du
9
n #1
n #1
Transcribed Image Text:16. 17. 18. 19. 20. 21. 22. [²√a + bu du = Tu S 1 u√a+bu [³ S- S 1 √√a+bu a + bu น a + bu Un -du -du = U √a + bu du = -du un /a + bu = du = du = 2 b (2n + 3) 1 √á -In 2 -[uº{(a + bu)²"'* _ na fu²+¹ √/a + bu du] ³/2 - -1 a (n − 1) √a+bu - √a √a+bu + √a :arctan a (n − 1) (2n + 2√a+bu+a af. -2 (2a - bu) 36² √a + bu un-1 a + bu 2 + 1)6 (2² -a + 1 u√a + bu | (2n − 3)b ſ 2 5 ( u² √a + bu - + C, a > 0 −1 17 [(a + dujt², (2n = 536 / Va + bu du] · bu) ³/2 - 5)b √a + 2 UT-1 a + bu + C +C, a <0 du 1 un-1√a+bu na ªf. un-1 √a + bu du du 9 n #1 n #1
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