hello, i don't really want you to solve for anything, i just want to know what rules did this solution apply and what part it belongs please kindly indicate.I need to know what is the specific rule used and what part please kindly label it, since my teacher does not discuss these things.ps. this is partial derivatives 2– 2n)" = y- xzDifferrontiatewithtakingnespert fo z andX asa cans fant.he→ * (2-2)", 7(2-20" (1-0) = - x(uv) = uv+ uv']» (2-2»)" a - 37- - - y(2-20)*"10039he100he- (2- 2%)y9999heay99x t 100g (Z-2x)1- (2- 2x)0n + lo0(2-22)91-(2- 2n) l00个 y (2- 2x)" - y-xzDiffemetinte Xi pantialy to yo taking za eonstont.with nespeetas- x 2)%3D→ 1.(2- 2,)"+ J-100(2-2,)"(0- 299= 1-2十人%3D7-200y (2-22)"+ * = 1- (2- 2%]lo02-2n- 2007 (2-205)l001-|- (2-22)"2 - 200y(2-21)91-(2 - 2)1509002 - 200 y(2-2n)*1介

Answered: Image /qna-images/answer/4a00fc7b-0a8e-47f1-a20e-56fe29cf750d.jpg

2- oiffemontiake with nespeef fo z and ataking X as a cams fant. he * (2-2a)" y.l00 (2-2x)" (1-0) = 99 [(uv) = uv+ uv] %3D (2-2x 2- 2x)". the 99 i-(2- 2a)"/ he 2- 2x 99 99 n+ 100g (Z-22]7 1- (2- 22 lo0 n + l00(2-2) 1-(2- 2m) l00 ON

2- oiffemontiake with nespeef fo z and ataking X as a cams fant. he * (2-2a)" y.l00 (2-2x)" (1-0) = 99 [(uv) = uv+ uv] %3D (2-2x 2- 2x)". the 99 i-(2- 2a)"/ he 2- 2x 99 99 n+ 100g (Z-22]7 1- (2- 22 lo0 n + l00(2-2) 1-(2- 2m) l00 ON

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter9: Systems Of Equations And Inequalities

Section9.10: Partial Fractions

Problem 12E

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Question

hello, i don't really want you to solve for anything, i just want to know what rules did this solution apply and what part it belongs please kindly indicate.

I need to know what is the specific rule used and what part please kindly label it, since my teacher does not discuss these things.

ps. this is partial derivatives

2– 2n)" = y- xz
Differrontiate
with
taking
nespert fo z and
X as
a cans fant.
he
→ * (2-2)", 7(2-20" (1-0) = - x
(uv) = uv+ uv']
» (2-2»)" a - 37- - - y(2-20)*"
100
39
he
100
he
- (2- 2%)y
99
99
he
ay
99
x t 100g (Z-2x)
1- (2- 2x)0
n + lo0(2-22)9
1-(2- 2n) l00
个

y (2- 2x)" - y-xz
Diffemetinte Xi pantialy to yo taking z
a eonstont.
with nespeet
as
- x 2)
%3D
→ 1.(2- 2,)"+ J-100(2-2,)"(0- 2
99
= 1-2
十人
%3D
7-200y (2-22)"
+ * = 1- (2- 2%]lo0
2-2n
- 2007 (2-205)
l00
1-
|- (2-22)"
2 - 200y(2-21)9
1-(2 - 2)150
900
2 - 200 y(2-2n)*1
介

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